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Pertanyaan

Tentukan nilai limit berikut. x → − 3 lim ​ 3 x 2 + 3 x − 18 2 x 2 − x − 21 ​

Tentukan nilai limit berikut.

 

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S. Yoga

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Jawaban

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 limit as x rightwards arrow thin space minus 3 of open parentheses fraction numerator 2 x squared minus x minus 21 over denominator 3 x plus 3 x minus 18 end fraction close parentheses equals 0.

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Pembahasan

Mencari nilai limit: Jadi, .

Mencari nilai limit:

limit as x rightwards arrow thin space minus 3 of open parentheses fraction numerator 2 x squared minus x minus 21 over denominator 3 x plus 3 x minus 18 end fraction close parentheses equals fraction numerator 2 open parentheses negative 3 close parentheses squared minus open parentheses negative 3 close parentheses minus 21 over denominator 3 open parentheses negative 3 close parentheses plus 3 open parentheses negative 3 close parentheses minus 18 end fraction equals fraction numerator 2 times 9 minus open parentheses negative 3 close parentheses minus 21 over denominator negative 9 minus 9 minus 18 end fraction equals fraction numerator 18 minus open parentheses negative 3 close parentheses minus 21 over denominator negative 36 end fraction equals fraction numerator 0 over denominator negative 36 end fraction equals 0 

Jadi, limit as x rightwards arrow thin space minus 3 of open parentheses fraction numerator 2 x squared minus x minus 21 over denominator 3 x plus 3 x minus 18 end fraction close parentheses equals 0.

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