Roboguru

Tentukan nilai  dengan konsep OBE.

Pertanyaan

Tentukan nilai begin mathsize 14px style left parenthesis x comma y comma z right parenthesis end style dengan konsep OBE.

begin mathsize 14px style open parentheses table row cell negative 3 end cell 1 0 row 2 0 1 row cell negative 1 end cell 3 cell negative 2 end cell end table close parentheses open parentheses table row x row y row z end table close parentheses equals open parentheses table row 3 row cell negative 4 end cell row 2 end table close parentheses end style 

Pembahasan Soal:

Terlebih dahulu mengubah dalam bentuk matriks berikut :

open parentheses table row cell negative 3 end cell 1 0 row 2 0 1 row cell negative 1 end cell 3 cell negative 2 end cell end table open vertical bar table row 3 row cell negative 4 end cell row 2 end table close vertical bar close parentheses Baris space 1 space colon left parenthesis negative 3 right parenthesis space left parenthesis agar space straight B subscript 11 equals 1 right parenthesis open parentheses table row 1 cell fraction numerator negative 1 over denominator 3 end fraction end cell 0 row 2 0 1 row cell negative 1 end cell 3 cell negative 2 end cell end table open vertical bar table row cell negative 1 end cell row cell negative 4 end cell row 2 end table close vertical bar close parentheses Baris space 2 space rightwards double arrow straight B subscript 2 minus 2 straight B subscript 1 space dan space Baris space 3 rightwards double arrow space space straight B subscript 3 plus straight B subscript 1 open parentheses table row 1 cell fraction numerator negative 1 over denominator 3 end fraction end cell 0 row 0 cell 2 over 3 end cell 1 row 0 cell 2 2 over 3 end cell cell negative 2 end cell end table open vertical bar table row cell negative 1 end cell row cell negative 2 end cell row 1 end table close vertical bar close parentheses Baris space 2 rightwards double arrow straight B subscript 2 x 3 over 2 open parentheses table row 1 cell fraction numerator negative 1 over denominator 3 end fraction end cell 0 row 0 1 cell 3 over 2 end cell row 0 cell 2 2 over 3 end cell cell negative 2 end cell end table open vertical bar table row cell negative 1 end cell row cell negative 3 end cell row 1 end table close vertical bar close parentheses Baris space 3 rightwards double arrow straight B subscript 3 minus 2 2 over 3 straight B subscript 2 open parentheses table row 1 cell fraction numerator negative 1 over denominator 3 end fraction end cell 0 row 0 1 cell 3 over 2 end cell row 0 0 cell negative 4 end cell end table open vertical bar table row cell negative 1 end cell row cell negative 3 end cell row 5 end table close vertical bar close parentheses Baris space 3 rightwards double arrow space straight B subscript 3 colon negative 4 open parentheses table row 1 cell fraction numerator negative 1 over denominator 3 end fraction end cell 0 row 0 1 cell 3 over 2 end cell row 0 0 1 end table open vertical bar table row cell negative 1 end cell row cell negative 3 end cell row cell fraction numerator negative 5 over denominator 4 end fraction end cell end table close vertical bar close parentheses Maka Baris space ke space 3 space diperoleh space straight z equals fraction numerator negative 5 over denominator 4 end fraction Baris space ke space 2 space diperoleh space straight y plus 3 over 2 straight z equals negative 3 straight y equals negative 3 minus open parentheses 3 over 2 close parentheses open parentheses fraction numerator negative 5 over denominator 4 end fraction close parentheses straight y equals fraction numerator negative 9 over denominator 8 end fraction Baris space ke space 1 space diperoleh straight x plus straight y plus 0. straight z equals negative 1 straight x plus fraction numerator negative 9 over denominator 8 end fraction equals 3 straight x equals 33 over 8   

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell Sehingga space diperoleh space nilai end cell row straight x equals cell 33 over 8 end cell row straight y equals cell fraction numerator negative 9 over denominator 8 end fraction end cell row straight z equals cell fraction numerator negative 5 over denominator 4 end fraction end cell end table  

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 19 Juli 2021

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