Iklan

Pertanyaan

Tentukan limit dari fungsi berikut! d. x → 1 lim ​ 3 x + 1 ​ + 5 x − 4 ​ 2 x + 2 ​ − 2 x − 1 ​ ​

Tentukan limit dari fungsi berikut! 

d.  

8 dari 10 siswa nilainya naik

dengan paket belajar pilihan

Habis dalam

01

:

20

:

46

:

24

Klaim

Iklan

A. Salim

Master Teacher

Mahasiswa/Alumni Universitas Pelita Harapan

Jawaban terverifikasi

Jawaban

.

 begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as straight x rightwards arrow 1 of end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator square root of 2 straight x plus 2 end root minus square root of 2 straight x minus 1 end root over denominator square root of 3 straight x plus 1 end root plus square root of 5 straight x minus 4 end root end fraction end cell end table equals 1 third end style

Pembahasan

Pembahasan
lock

Jadi .

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as straight x rightwards arrow 1 of fraction numerator square root of 2 straight x plus 2 end root minus square root of 2 straight x minus 1 end root over denominator square root of 3 straight x plus 1 end root plus square root of 5 straight x minus 4 end root end fraction end cell equals cell fraction numerator square root of 2 open parentheses 1 close parentheses plus 2 end root minus square root of 2 open parentheses 1 close parentheses minus 1 end root over denominator square root of 3 open parentheses 1 close parentheses plus 1 end root plus square root of 5 open parentheses 1 close parentheses minus 4 end root end fraction end cell row blank equals cell fraction numerator square root of 4 minus square root of 1 over denominator square root of 4 plus square root of 1 end fraction end cell row blank equals cell fraction numerator 2 minus 1 over denominator 2 plus 1 end fraction end cell row blank equals cell 1 third end cell end table end style 

Jadi begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as straight x rightwards arrow 1 of end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator square root of 2 straight x plus 2 end root minus square root of 2 straight x minus 1 end root over denominator square root of 3 straight x plus 1 end root plus square root of 5 straight x minus 4 end root end fraction end cell end table equals 1 third end style

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Pertanyaan serupa

x → − 1 lim ​ x 2 + 4 x + 3 x 2 − 1 ​ = ...

1

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia