Pertanyaan

Tentukan deret 1 2 + 3 2 + 5 2 + ⋯ sampai dengan n suku ....

Tentukan deret $1^{2} + 3^{2} + 5^{2} + \dots$ sampai dengan n suku ....

$fraction numerator n left parenthesis 3 n plus 2 right parenthesis left parenthesis 2 n minus 1 right parenthesis over denominator 3 end fraction$
$fraction numerator n left parenthesis 2 n plus 2 right parenthesis left parenthesis 2 n minus 1 right parenthesis over denominator 3 end fraction$
$fraction numerator 2 n left parenthesis n plus 1 right parenthesis left parenthesis n minus 1 right parenthesis over denominator 3 end fraction$
$fraction numerator 2 left parenthesis n plus 1 right parenthesis left parenthesis 2 n minus 1 right parenthesis over denominator 2 end fraction$
$fraction numerator 2 plus left parenthesis n minus 1 right parenthesis left parenthesis 16 plus 8 left parenthesis n minus 2 right parenthesis right parenthesis over denominator 2 end fraction$

F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

Jawaban terverifikasi

Jawaban

tidak ada jawaban yang benar pada Opsi.

Pembahasan

Dengan menggunakan aturan dan sifat notasi sigma maka didapatkan Oleh karena itu, tidak ada jawaban yang benar pada Opsi.

Dengan menggunakan aturan dan sifat notasi sigma maka didapatkan

$table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 1 squared plus 3 squared plus 5 squared plus midline horizontal ellipsis end cell row blank equals cell sum from i equals 1 to n of left parenthesis 2 i minus 1 right parenthesis squared end cell row blank equals cell sum from i equals 1 to n of 4 i squared minus 4 i plus 1 end cell row blank equals cell 4 sum from i equals 1 to n of i squared minus 4 sum from i equals 1 to n of i plus sum from i equals 1 to n of 1 end cell row blank equals cell 4 open square brackets fraction numerator n open parentheses n plus 1 close parentheses open parentheses 2 n plus 1 close parentheses over denominator 6 end fraction close square brackets minus 4 open square brackets fraction numerator n open parentheses n plus 1 close parentheses over denominator 2 end fraction close square brackets plus n end cell row blank equals cell fraction numerator 2 n open parentheses n plus 1 close parentheses open parentheses 2 n plus 1 close parentheses over denominator 3 end fraction minus 2 n left parenthesis n plus 1 right parenthesis plus n end cell row blank equals cell n over 3 open square brackets 2 open parentheses n plus 1 close parentheses open parentheses 2 n plus 1 close parentheses minus 6 open parentheses n plus 1 close parentheses plus 3 close square brackets end cell row blank equals cell n over 3 open square brackets 2 open parentheses n plus 1 close parentheses open parentheses 2 n minus 2 close parentheses plus 3 close square brackets end cell row blank equals cell n over 3 open square brackets 4 open parentheses n plus 1 close parentheses open parentheses n minus 1 close parentheses plus 3 close square brackets end cell row blank equals cell n over 3 open square brackets 4 open parentheses n squared minus 1 close parentheses plus 3 close square brackets end cell row blank equals cell n over 3 open square brackets 4 n squared minus 4 plus 3 close square brackets end cell row blank equals cell n over 3 open square brackets 4 n squared minus 1 close square brackets end cell row blank equals cell fraction numerator n left parenthesis 2 n plus 1 right parenthesis left parenthesis 2 n minus 1 right parenthesis over denominator 3 end fraction end cell end table$

Oleh karena itu, tidak ada jawaban yang benar pada Opsi.