Roboguru

Suatu rantai aliran yang bercabang terdiri dari 3 kawat baja yang dihubungkan paralel. Perbandingan panjang kawat baja ini adalah 1 : 3 : 5 dan perbandingan luas penampangnya 3 : 4 : 1. Hambatan cabang pertama 10 ohm. Hitung hambatan pada cabang yang lain!

Pertanyaan

Suatu rantai aliran yang bercabang terdiri dari 3 kawat baja yang dihubungkan paralel. Perbandingan panjang kawat baja ini adalah 1 : 3 : 5 dan perbandingan luas penampangnya 3 : 4 : 1. Hambatan cabang pertama 10 ohm. Hitung hambatan pada cabang yang lain!

Pembahasan Soal:

Diketahui :

𝓁 subscript 1 space colon space 𝓁 subscript 1 space colon space 𝓁 subscript 1 equals 1 space colon space 3 space colon space 5 italic A subscript 1 space colon space italic A subscript 1 space colon space italic A subscript 1 equals 3 space colon space 4 space colon space 1 italic R subscript 1 equals 10 space capital omega I equals 3 comma 4 space A

 

Pembahasan :

Perbandingan hambatan

italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 equals italic rho 𝓁 subscript 1 over italic A subscript 1 space colon space italic rho 𝓁 subscript 2 over italic A subscript 2 space colon space italic rho 𝓁 subscript 3 over italic A subscript 3 italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 equals 𝓁 subscript 1 over italic A subscript 1 space colon space 𝓁 subscript 2 over italic A subscript 2 space colon space 𝓁 subscript 3 over italic A subscript 3 italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 equals 1 third space colon space 3 over 4 space colon space 5 over 1 

 

Hambatan R2 dan R3

table attributes columnalign right center left columnspacing 0px end attributes row cell italic R subscript 2 end cell equals cell fraction numerator bevelled 3 over 4 over denominator bevelled 1 third end fraction cross times 10 space capital omega space equals 22 comma 5 space capital omega space end cell row cell italic R subscript 3 end cell equals cell fraction numerator 5 over denominator bevelled 1 third end fraction cross times 10 space capital omega space equals 15 space capital omega space end cell end table 

Jadi, hambatan pada cabang lain sebesar 22,5 ohm dan 15 ohm.

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

H. Ishfahani

Mahasiswa/Alumni Universitas Negeri Malang

Terakhir diupdate 27 Mei 2021

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

Tapi Roboguru masih mau belajar. Menurut kamu pembahasan kali ini sudah membantu, belum?

Membantu

Kurang Membantu

Apakah pembahasan ini membantu?

Belum menemukan yang kamu cari?

Post pertanyaanmu ke Tanya Jawab, yuk

Mau Bertanya

Pertanyaan yang serupa

Empat kawat perak disusun secara paralel. Perbandingan penampang kawat adalah 1 : 3 : 5 : 2 dan perbandingan panjangnya 6 : 4 : 3 : 1. Hambatan pada cabang pertama 420 ohm dan kuat arus utama (sebelum...

Pembahasan Soal:

Diketahui :

italic A subscript 1 space colon space italic A subscript 2 space colon space italic A subscript 3 space colon space italic A subscript 4 equals 1 space colon space 3 space colon space 5 space colon space 2 𝓁 subscript 1 space colon space 𝓁 subscript 2 space colon space 𝓁 subscript 3 space colon space 𝓁 subscript 4 equals 6 space colon space 4 space colon space 3 space colon space 1 italic R subscript 1 equals 420 space capital omega I equals 15 comma 8 space A 

 

Pembahasan :

Perbandingan hambatan

table attributes columnalign right center left columnspacing 0px end attributes row cell italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 italic space colon space italic R subscript italic 4 end cell equals cell italic rho 𝓁 subscript 1 over italic A subscript 1 space colon space italic rho 𝓁 subscript 2 over italic A subscript 2 space colon space italic rho 𝓁 subscript 3 over italic A subscript 3 end cell row cell italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 italic space colon space italic R subscript italic 4 end cell equals cell 𝓁 subscript 1 over italic A subscript 1 space colon space 𝓁 subscript 2 over italic A subscript 2 space colon space 𝓁 subscript 3 over italic A subscript 3 end cell row cell italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 italic space colon space italic R subscript italic 4 end cell equals cell 6 over 1 space colon space 4 over 3 space colon space 3 over 5 space colon 1 half end cell end table  

 

Hambatan pada masing-masing cabang

table attributes columnalign right center left columnspacing 0px end attributes row cell italic R subscript 2 end cell equals cell fraction numerator bevelled 4 over 3 over denominator 6 end fraction cross times 420 space capital omega equals 280 over 3 space capital omega end cell row cell italic R subscript 3 end cell equals cell fraction numerator bevelled 3 over 5 over denominator 6 end fraction cross times 420 space capital omega equals 42 space capital omega end cell row cell italic R subscript 4 end cell equals cell fraction numerator bevelled 1 half over denominator 6 end fraction cross times 420 space capital omega equals 35 space capital omega end cell end table 

 

Hambatan pengganti susunan paralel

table attributes columnalign right center left columnspacing 0px end attributes row cell 1 over italic R subscript italic p end cell equals cell 1 over italic R subscript 1 plus 1 over italic R subscript 2 plus 1 over italic R subscript 3 plus 1 over italic R subscript 4 end cell row cell 1 over italic R subscript italic p end cell equals cell 1 over 420 plus fraction numerator 1 over denominator bevelled 280 over 3 end fraction plus 1 over 42 plus 1 over 35 end cell row cell 1 over italic R subscript italic p end cell equals cell fraction numerator 1 plus 4 comma 5 plus 10 plus 12 over denominator 420 end fraction end cell row cell italic R subscript italic p end cell equals cell 15 comma 27 space capital omega end cell end table 

 

Tegangan listrik rangkaian paralel (V = V= V= V= V4)

table attributes columnalign right center left columnspacing 0px end attributes row V equals cell I italic R subscript italic p end cell row blank equals cell left parenthesis 15 comma 8 right parenthesis left parenthesis 15 comma 27 right parenthesis end cell row blank equals cell 241 comma 26 space V end cell end table 

 

Kuat arus pada masing-masing cabang

table attributes columnalign right center left columnspacing 0px end attributes row cell I subscript 1 end cell equals cell V subscript 1 over italic R subscript 1 equals fraction numerator 241 comma 26 over denominator 420 end fraction equals 0 comma 57 space A end cell row cell I subscript 2 end cell equals cell V subscript 2 over italic R subscript 2 equals fraction numerator 241 comma 26 over denominator bevelled 280 over 3 end fraction equals 2 comma 59 space A end cell row cell I subscript 3 end cell equals cell V subscript 3 over italic R subscript 3 equals fraction numerator 241 comma 26 over denominator 542 end fraction equals 5 comma 7 space A end cell row cell I subscript 4 end cell equals cell V subscript 4 over italic R subscript 4 equals fraction numerator 241 comma 26 over denominator 35 end fraction equals 6 comma 89 space A end cell end table 

Jadi, kuat arus pada masing-masing cabang sebesar 0,57 A; 2,59 A; 5,7 A; dan 6,89 A.

0

Roboguru

Suatu rantai aliran yang bercabang terdiri dari 3 kawat besi paralel yang panjangnya berbanding sebagai 2 : 1 : 3. Hambatan kawat berbanding sebagai 1 : 2 : 4. Penampang kawat pada cabang pertama adal...

Pembahasan Soal:

Diketahui :

𝓁 subscript 1 space colon space 𝓁 subscript 2 space colon space 𝓁 subscript 3 equals 2 space colon space 1 space colon space 3 italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 equals 1 space colon space 2 space colon space 4 italic A subscript 1 equals 6 space mm squared I subscript 3 equals 2 space A 

 

Pembahasan :

Perbandingan luas penampang

italic R equals italic rho 𝓁 over italic A italic A equals italic rho 𝓁 over italic R  italic A subscript 1 space colon space italic A subscript 1 space colon space italic A subscript 1 equals italic rho 𝓁 subscript 1 over italic R subscript 1 space colon space italic rho 𝓁 subscript 2 over italic R subscript 2 space colon space italic rho 𝓁 subscript 3 over italic R subscript 3 italic A subscript 1 space colon space italic A subscript 1 space colon space italic A subscript 1 equals 𝓁 subscript 1 over italic R subscript 1 space colon space 𝓁 subscript 2 over italic R subscript 2 space colon space 𝓁 subscript 3 over italic R subscript 3 italic A subscript 1 space colon space italic A subscript 1 space colon space italic A subscript 1 equals 2 over 1 space colon space 1 half space colon space 3 over 2 

 

Luas penampang kawat pada cabang yang lain

italic A subscript 2 equals fraction numerator bevelled 1 half over denominator 2 end fraction cross times 6 space mm squared equals 1 comma 5 space mm squared italic A subscript 3 equals fraction numerator bevelled 3 over 4 over denominator 2 end fraction cross times 6 space mm squared equals 2 comma 25 space mm squared 

Jadi, luas penampang kawat pada cabang lainnya sebesar 1,5 mm2 dan 2,25 mm2.

0

Roboguru

Tiga kawat yang sama jenisnya dengan perbandingan panjangnya 3 : 2 : 1 dan perbandingan penampang 6 : 1 : 5 dihubungkan seri. Jika potensial listrik pada kawat pertama 60 volt, hitung potensial listri...

Pembahasan Soal:

Diketahui :

𝓁 subscript 1 space colon space 𝓁 subscript 2 space colon space 𝓁 subscript 3 equals 3 space colon space 2 space colon space 1 italic A subscript 1 space colon space italic A subscript 2 space colon space italic A subscript 2 equals 6 space colon space 1 space colon space 5 V subscript 1 equals 60 space V italic R subscript 1 equals 120 space capital omega 

 

Pembahasan :

Perbandingan hambatan

italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 space equals space italic rho 𝓁 subscript 1 over italic A subscript 1 space colon space italic rho 𝓁 subscript 2 over italic A subscript 2 space colon space italic rho 𝓁 subscript 3 over italic A subscript 3 italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 space equals 𝓁 subscript 1 over italic A subscript 1 space colon space 𝓁 subscript 2 over italic A subscript 2 space colon space 𝓁 subscript 3 over italic A subscript 3 italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 space equals 3 over 6 space colon space 2 over 1 space colon space 1 fifth italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 space equals 0 comma 5 space colon space 2 space colon space 0 comma 2 

 

Arus listrik yang mengalir

table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript 1 end cell equals cell I italic R subscript 1 end cell row 60 equals cell I left parenthesis 120 right parenthesis end cell row I equals cell 0 comma 5 space A end cell end table 

 

Potensial listrik kawat kedua dan kawat ketiga

table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript 2 end cell equals cell I italic R subscript 2 end cell row blank equals cell left parenthesis 0 comma 5 right parenthesis open parentheses fraction numerator 2 over denominator 0 comma 5 end fraction cross times 120 close parentheses end cell row blank equals cell left parenthesis 0 comma 5 right parenthesis left parenthesis 480 right parenthesis end cell row blank equals cell 240 space V end cell row blank blank blank row cell V subscript 3 end cell equals cell I italic R subscript 3 end cell row blank equals cell italic left parenthesis italic 0 italic comma italic 5 italic right parenthesis begin italic style left parenthesis fraction numerator straight 2 over denominator straight 0 straight comma straight 2 end fraction straight cross times straight 120 right parenthesis end style end cell row blank equals cell left parenthesis 0 comma 5 right parenthesis left parenthesis 48 right parenthesis end cell row blank equals cell 24 space V end cell end table

Jadi, potensial listrik pada kawat yang lain sebesar 240 V dan 24 V.

0

Roboguru

Suatu rantai aliran yang bercabang terdiri dari 3 kawat besi paralel yang panjangnya berbanding sebagai 2 : 1 : 3. Hambatan kawat berbanding sebagai 1 : 2 : 4. Penampang kawat pada cabang pertama adal...

Pembahasan Soal:

Diketahui :

𝓁 subscript 1 space colon space 𝓁 subscript 2 space colon space 𝓁 subscript 3 equals 2 space colon space 1 space colon space 3 italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 equals 1 space colon space 2 space colon space 4 italic A subscript 1 equals 6 space mm squared I subscript 3 equals 2 space A 

 

Pembahasan :

Pada rangkaian paralel berlaku

V = V1 = V2 = V3

I = I+ I+ I3

Maka, perbandingan kuat arusnya

table attributes columnalign right center left columnspacing 0px end attributes row cell I subscript 1 space colon space I subscript 2 space colon space I subscript 3 space end cell equals cell V subscript 1 over italic R subscript 1 space colon space V subscript 2 over italic R subscript 2 space colon space V subscript 3 over italic R subscript 3 end cell row cell I subscript 1 space colon space I subscript 2 space colon space I subscript 3 space end cell equals cell V over 1 space colon space V over 2 space colon space V over 4 end cell row cell I subscript 1 space colon space I subscript 2 space colon space I subscript 3 space end cell equals cell 1 over 1 space colon space 1 half space colon space 1 fourth end cell end table 

 

Kuat arus pada cabang yang lain

table attributes columnalign right center left columnspacing 0px end attributes row cell I subscript 1 end cell equals cell fraction numerator 1 over denominator bevelled 1 fourth end fraction cross times 2 space A equals 8 space A end cell row cell I subscript 2 end cell equals cell fraction numerator bevelled 1 half over denominator bevelled 1 fourth end fraction cross times 2 space A equals 4 space A end cell end table 

 

Kuat arus utama

table attributes columnalign right center left columnspacing 0px end attributes row I equals cell I subscript 1 and I subscript 2 and I subscript 3 end cell row blank equals cell 8 plus 4 plus 2 end cell row blank equals cell 14 space A end cell end table 

Jadi, kuat arus pada cabang yang lain sebesar 8 A dan 4 A. Kuat arus utama sebesar 14 A.

 

0

Roboguru

Suatu rantai aliran yang bercabang terdiri dari 3 kawat baja yang dihubungkan paralel. Perbandingan panjang kawat baja ini adalah 1 : 3 : 5 dan perbandingan luas penampangnya 3 : 4 : 1. Jika rantai al...

Pembahasan Soal:

Diketahui :

space 𝓁 subscript 1 space colon space 𝓁 subscript 1 space colon space 𝓁 subscript 1 equals 1 space colon space 3 space colon space 5 italic A subscript 1 space colon space italic A subscript 1 space colon space italic A subscript 1 equals 3 space colon space 4 space colon space 1 italic R subscript 1 equals 10 space capital omega I equals 3 comma 4 space italic A 

 

Pembahasan :

Perbandingan hambatan

italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 equals italic rho 𝓁 subscript 1 over italic A subscript 1 space colon space italic rho 𝓁 subscript 2 over italic A subscript 2 space colon space italic rho 𝓁 subscript 3 over italic A subscript 3 italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 equals 𝓁 subscript 1 over italic A subscript 1 space colon space 𝓁 subscript 2 over italic A subscript 2 space colon space 𝓁 subscript 3 over italic A subscript 3 italic R subscript 1 space colon space italic R subscript 2 space colon space italic R subscript 3 equals 1 third space colon space 3 over 4 space colon space 5 over 1 

 

Hambatan pada cabang lain

italic R subscript 2 equals fraction numerator bevelled 3 over 4 over denominator bevelled 1 third end fraction cross times 10 space capital omega space equals 22 comma 5 space capital omega italic R subscript 3 equals fraction numerator 5 over denominator bevelled 1 third end fraction cross times 10 space capital omega space equals 15 space capital omega 

 

Hambatan pengganti susunan paralel

table attributes columnalign right center left columnspacing 0px end attributes row cell 1 over italic R subscript italic p end cell equals cell 1 over italic R subscript 1 plus 1 over italic R subscript 2 plus 1 over italic R subscript 3 end cell row cell 1 over italic R subscript italic p end cell equals cell 1 over 10 plus fraction numerator 1 over denominator 22 comma 5 end fraction plus 1 over 150 end cell row cell 1 over italic R subscript italic p end cell equals cell fraction numerator 45 plus 20 plus 3 over denominator 450 end fraction end cell row cell italic R subscript italic p end cell equals cell 6 comma 62 space capital omega end cell end table 

 

Tegangan pada rangkaian paralel (V = V1 = V2 = V3)

table attributes columnalign right center left columnspacing 0px end attributes row V equals cell I italic R subscript italic p end cell row blank equals cell left parenthesis 3 comma 4 right parenthesis left parenthesis 6 comma 62 right parenthesis end cell row blank equals cell 22 comma 5 space V end cell row blank blank blank end table 

 

Arus pada masing-masing cabang

table attributes columnalign right center left columnspacing 0px end attributes row cell I subscript 1 end cell equals cell V over italic R subscript 1 equals fraction numerator 22 comma 5 over denominator 10 end fraction equals 2 comma 25 space A end cell row cell I subscript 2 end cell equals cell V over italic R subscript 2 equals fraction numerator 22 comma 5 over denominator 22 comma 5 end fraction equals 1 space A end cell row cell I subscript 3 end cell equals cell V over italic R subscript 3 equals fraction numerator 22 comma 5 over denominator 150 end fraction equals 0 comma 15 space A end cell end table

Jadi, arus pada masinh-masing cabang sebesar 2,25 A, 1 A, dan 0,15 A.

0

Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

Tapi Roboguru masih mau belajar. Menurut kamu pembahasan kali ini sudah membantu, belum?

Membantu

Kurang Membantu

Apakah pembahasan ini membantu?

Belum menemukan yang kamu cari?

Post pertanyaanmu ke Tanya Jawab, yuk

Mau Bertanya

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved