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Suatu persamaan reaksi redoks adalah sebagai berikut: setelah setara harga a, b, c, d berturut – turut adalah ….

Suatu persamaan reaksi redoks adalah sebagai berikut:

bold italic a bold space bold italic M bold italic n bold italic O subscript bold 4 to the power of bold minus bold space bold plus bold space bold italic b bold space bold italic C subscript bold 2 bold italic O subscript bold 4 to the power of bold minus bold 2 end exponent bold space bold plus bold space bold italic c bold space bold italic H to the power of bold plus bold space bold rightwards arrow bold italic d bold space bold italic C bold italic O subscript bold 2 bold space bold plus bold space bold space bold italic M bold italic n to the power of bold plus bold 2 end exponent bold space bold plus bold space bold italic H subscript bold 2 bold italic O bold space

setelah setara harga a, b, c, d berturut – turut adalah ….

  1. 1,8,3,1

  2. 3,6,1,8

  3. 2, 6, 16, 12

  4. 2, 5, 16, 10

  5. 1,8,3,6

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R. RGFREELANCETIGASATU

Master Teacher

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Reduksi: Oksidasi: _______________________________+

Reduksi:        M n O subscript 4 to the power of minus space plus space 8 space H to the power of plus space plus space 5 e rightwards arrow space M n to the power of plus 2 end exponent space plus space 4 H subscript 2 O space  

Oksidasi:       C subscript 2 O subscript 4 to the power of negative 2 end exponent space rightwards arrow space 2 C O subscript 2 space plus 2 e 

                      bold 2 bold italic M bold italic n bold italic O subscript bold 4 to the power of bold minus bold space bold plus bold space bold 16 bold space bold italic H to the power of bold plus bold space bold plus bold space bold 10 bold space bold italic e bold rightwards arrow bold space bold 2 bold space bold italic M bold italic n to the power of bold plus bold 2 end exponent bold space bold plus bold space bold 8 bold space bold italic H subscript bold 2 bold italic O bold space  

                      bold 5 bold space bold italic C subscript bold 2 bold italic O subscript bold 4 to the power of bold minus bold 2 end exponent bold space bold rightwards arrow bold space bold 10 bold space bold italic C bold italic O subscript bold 2 bold space bold plus bold space bold 10 bold space bold italic e 

                       _______________________________+

                     bold 5 bold space bold italic M bold italic n bold italic O subscript bold 4 to the power of bold minus bold space bold plus bold space bold 16 bold space bold italic H to the power of bold plus bold space bold plus bold 5 bold space bold italic C subscript bold 2 bold italic O subscript bold 4 to the power of bold minus bold 2 end exponent bold rightwards arrow bold space bold 2 bold space bold italic M bold italic n to the power of bold plus bold 2 end exponent bold space bold plus bold space bold 8 bold space bold italic H subscript bold 2 bold italic O bold space bold plus bold space bold 10 bold space bold italic C bold italic O subscript bold 2

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

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Diketahui reaksi redoks berikut (reaksi belum setara) : MnO 4 - (aq) + I - (aq) → MnO 2(s) + I 2(aq) Jika reaksi terjadi pada suasana basa, maka reaksi setaranya adalah .....

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