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Pertanyaan

Solve the following pairs of simultaneous equations. c. { x + y = 2 a x + y = 2 a 3 ​

Solve the following pairs of simultaneous equations.

c.    

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Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta

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Jawaban

himpunan penyelesaian darisistem persamaan tersebut adalah .

 himpunan penyelesaian dari sistem persamaan tersebut adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open curly brackets open parentheses 2 a squared plus 2 a plus 2 comma negative 2 a squared minus 2 a close parentheses close curly brackets end cell end table.

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Pembahasan

Menentukan penyelesaian SPLDV dengan Metode Cramer (Metode Determinan) adalah sebagai berikut: ditentukan oleh: dengan Diketahuipersamaan: Dicari masing-masing determinan dandidapatkan: Sehingga penyelesaiannya didapatkan: Jadi,himpunan penyelesaian darisistem persamaan tersebut adalah .

Menentukan penyelesaian SPLDV dengan Metode Cramer (Metode Determinan) adalah sebagai berikut:

table attributes columnalign right center left columnspacing 0px end attributes row blank blank a end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank x end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank b end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank y end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank e end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank c end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank x end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank d end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank y end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank f end table  

ditentukan oleh:

x equals D subscript x over D space dan space y equals D subscript y over D  

dengan

D equals open vertical bar table row a b row c d end table close vertical bar equals a d minus b c D subscript x equals open vertical bar table row e b row f d end table close vertical bar equals e d minus b f D subscript y equals open vertical bar table row a e row c f end table close vertical bar equals a f minus e c  

Diketahui persamaan:

table attributes columnalign left end attributes row cell x plus y equals 2 end cell row cell a x plus y equals 2 a cubed end cell end table    

Dicari masing-masing determinan D comma space D subscript x comma space dan space D subscript y dan didapatkan:

table attributes columnalign right center left columnspacing 0px end attributes row D equals cell open vertical bar table row 1 1 row a 1 end table close vertical bar end cell row D equals cell open parentheses 1 close parentheses open parentheses 1 close parentheses minus open parentheses 1 close parentheses open parentheses a close parentheses end cell row blank equals cell 1 minus a end cell row blank blank blank row D equals cell open vertical bar table row 2 1 row cell 2 a cubed end cell 1 end table close vertical bar end cell row cell D subscript x end cell equals cell open parentheses 2 close parentheses open parentheses 1 close parentheses minus open parentheses 1 close parentheses open parentheses 2 a cubed close parentheses end cell row blank equals cell 2 minus 2 a cubed end cell row blank blank blank row cell D subscript y end cell equals cell open vertical bar table row 1 2 row a cell 2 a cubed end cell end table close vertical bar end cell row cell D subscript y end cell equals cell open parentheses 1 close parentheses open parentheses 2 a cubed close parentheses minus open parentheses 2 close parentheses open parentheses a close parentheses end cell row blank equals cell 2 a cubed minus 2 a end cell end table       

Sehingga penyelesaiannya didapatkan:

table attributes columnalign right center left columnspacing 0px end attributes row x equals cell fraction numerator 2 minus 2 a cubed over denominator 1 minus a end fraction end cell row blank equals cell fraction numerator 2 open parentheses 1 minus a cubed close parentheses over denominator 1 minus a end fraction end cell row blank equals cell fraction numerator 2 up diagonal strike open parentheses 1 minus a close parentheses end strike open parentheses a squared plus a plus 1 close parentheses over denominator up diagonal strike open parentheses 1 minus a close parentheses end strike end fraction end cell row blank equals cell 2 open parentheses a squared plus a plus 1 close parentheses end cell row blank equals cell 2 a squared plus 2 a plus 2 end cell row blank blank blank row y equals cell fraction numerator 2 a cubed minus 2 a over denominator 1 minus a end fraction end cell row blank equals cell fraction numerator 2 a open parentheses a squared minus 1 close parentheses over denominator 1 minus a end fraction end cell row blank equals cell fraction numerator 2 a open parentheses a plus 1 close parentheses open parentheses a minus 1 close parentheses over denominator open parentheses 1 minus a close parentheses end fraction end cell row blank equals cell fraction numerator 2 a open parentheses a plus 1 close parentheses up diagonal strike open parentheses a minus 1 close parentheses end strike over denominator negative up diagonal strike open parentheses a minus 1 close parentheses end strike end fraction end cell row blank equals cell negative 2 a open parentheses a plus 1 close parentheses end cell row blank equals cell negative 2 a squared minus 2 a end cell end table       

Jadi, himpunan penyelesaian dari sistem persamaan tersebut adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open curly brackets open parentheses 2 a squared plus 2 a plus 2 comma negative 2 a squared minus 2 a close parentheses close curly brackets end cell end table.

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Solve the following pairs of simultaneous equations. b. { x + y = 2 a x + y = a 2 + 1 ​

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