Pertanyaan

Segiempat ABCD sebangun dengan segiempat EFGH. a. Hitunglah x b. Hitunglah y c. p ∘ = … d. keliling EFGH keliling ABCD = … …

Segiempat ABCD sebangun dengan segiempat EFGH.

a. Hitunglah $x$

b. Hitunglah $y$

c. $p^{\circ} = \dots$

d. $\frac{keliling ABCD}{keliling EFGH} = \frac{\dots}{\dots}$

M. Mariyam

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Jawaban

$begin mathsize 14px style fraction numerator keliling space ABCD over denominator keliling space EFGH end fraction equals fraction numerator 46 comma 5 over denominator 37 comma 2 end fraction end style$

Pembahasan

Diketahui segiempat ABCD sebangun dengan segiempat EFGH, maka dan . a. Jadi, nilai Jadi, nilai Jadi, Jadi,

Diketahui segiempat ABCD sebangun dengan segiempat EFGH, maka

begin mathsize 14px style angle A equals angle E comma space angle B equals angle F comma space angle C equals angle G comma space angle D equals angle H end style dan

$begin mathsize 14px style fraction numerator A B over denominator E F end fraction equals fraction numerator B C over denominator F G end fraction equals fraction numerator C D over denominator G H end fraction equals fraction numerator A D over denominator E H end fraction end style$ .

a. $begin mathsize 14px style fraction numerator A B over denominator E F end fraction equals fraction numerator B C over denominator F G end fraction end style$

$begin mathsize 14px style fraction numerator 7 comma 5 over denominator 6 end fraction equals fraction numerator x over denominator 4 comma 8 end fraction x equals fraction numerator 7 comma 5 over denominator 6 end fraction open parentheses 4 comma 8 close parentheses x equals 6 end style$

Jadi, nilai begin mathsize 14px style x equals 6 end style

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight b. space fraction numerator A B over denominator E F end fraction end cell equals cell fraction numerator C D over denominator G H end fraction end cell row cell fraction numerator 7 comma 5 over denominator 6 end fraction end cell equals cell 18 over y end cell row cell 5 over 4 end cell equals cell 18 over y end cell row y equals cell fraction numerator 18 cross times 4 over denominator 5 end fraction end cell row blank equals cell 14 comma 4 end cell end table end style$

Jadi, nilai begin mathsize 14px style y equals 14 comma 4 end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight c. space angle straight B end cell equals cell angle straight F end cell row cell p degree end cell equals cell 150 degree end cell end table end style

Jadi, begin mathsize 14px style p degree equals 150 degree end style

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight d. fraction numerator keliling space ABCD over denominator keliling space EFGH end fraction end cell equals cell fraction numerator AB plus BC plus CD plus DA over denominator EF plus FG plus GH plus GE end fraction end cell row blank equals cell fraction numerator 7 comma 5 plus 6 plus 18 plus 15 over denominator 6 plus 4 comma 8 plus 14 comma 4 plus 12 end fraction end cell row blank equals cell fraction numerator 46 comma 5 over denominator 37 comma 2 end fraction end cell end table end style$

Jadi, $begin mathsize 14px style fraction numerator keliling space ABCD over denominator keliling space EFGH end fraction equals fraction numerator 46 comma 5 over denominator 37 comma 2 end fraction end style$