Pertanyaan

Sederhanakan dalam bentuk pangkat positif. ( 6 x 3 y 4 x y 2 ) 3 × ( 3 x 2 y − 2 2 x 3 y ) − 2

Sederhanakan dalam bentuk pangkat positif.

$(\frac{4 x y ^{2}}{6 x ^{3} y})^{3} \times (\frac{2 x ^{3} y}{3 x ^{2} y ^{- 2}})^{- 2}$

A. Salim

Master Teacher

Mahasiswa/Alumni Universitas Pelita Harapan

Jawaban terverifikasi

Jawaban

.

Pembahasan

Ingat kembali beberapasifat bilangan berpangkat berikut: Sehingga soal tersebut dapat kita hitung sebagai berikut: Jadi, .

Ingat kembali beberapa sifat bilangan berpangkat berikut:

Sehingga soal tersebut dapat kita hitung sebagai berikut:

$open parentheses fraction numerator 4 x y squared over denominator 6 x cubed y end fraction close parentheses cubed cross times open parentheses fraction numerator 2 x cubed y over denominator 3 x squared y to the power of negative 2 end exponent end fraction close parentheses to the power of negative 2 end exponent equals open parentheses 2 over 3 x to the power of 1 minus 3 end exponent y to the power of 2 minus 1 end exponent close parentheses cubed cross times open parentheses 2 over 3 x to the power of 3 minus 2 end exponent y to the power of 1 plus 2 end exponent close parentheses to the power of negative 2 end exponent equals open parentheses 2 over 3 x to the power of negative 2 end exponent y close parentheses cubed cross times open parentheses 2 over 3 x y cubed close parentheses to the power of negative 2 end exponent equals open parentheses begin display style 2 over 3 x to the power of negative 2 end exponent y end style close parentheses cubed over open parentheses begin display style 2 over 3 x y cubed end style close parentheses squared equals fraction numerator open parentheses begin display style 2 over 3 end style close parentheses cubed x to the power of negative 6 end exponent y cubed over denominator open parentheses begin display style 2 over 3 end style close parentheses squared x squared y to the power of 6 end fraction equals open parentheses 2 over 3 close parentheses to the power of 3 minus 2 end exponent x to the power of negative 6 minus 2 end exponent y to the power of 3 minus 6 end exponent equals open parentheses 2 over 3 close parentheses x to the power of negative 8 end exponent y to the power of negative 3 end exponent equals fraction numerator 2 over denominator 3 x to the power of 8 y cubed end fraction$

Jadi, $open parentheses fraction numerator 4 x y squared over denominator 6 x cubed y end fraction close parentheses cubed cross times open parentheses fraction numerator 2 x cubed y over denominator 3 x squared y to the power of negative 2 end exponent end fraction close parentheses to the power of negative 2 end exponent equals fraction numerator 2 over denominator 3 x to the power of 8 y cubed end fraction$ .