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Sebuah foton (λ=0,4 nm) menumbuk elektron diam dan dibelokkan dengan sudut 15° dari arahnya semula. Tentukanlah panjang gelombang foton sesudah tumbukan.

Pertanyaan

Sebuah foton begin mathsize 14px style open parentheses lambda equals 0 comma 4 space nm close parentheses end style menumbuk elektron diam dan dibelokkan dengan sudut 15° dari arahnya semula. Tentukanlah panjang gelombang foton sesudah tumbukan.undefined

I. Fitriatmoko

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

jawabannya begin mathsize 14px style bold 0 bold comma bold 04968 bold cross times bold 10 to the power of bold minus bold 12 end exponent bold space bold m end style.

Pembahasan

Diketahui :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row lambda equals cell 0 comma 4 space nm equals 0 comma 4 cross times 10 to the power of negative 12 end exponent space straight m end cell row m equals cell 9 comma 1 cross times 10 to the power of negative 31 end exponent space kg end cell row c equals cell 3 cross times 10 to the power of 8 space straight m divided by straight s end cell row h equals cell 6 comma 6 cross times 10 to the power of negative 34 end exponent space Js end cell row theta equals cell 15 degree end cell end table end style 

Ditanya :

begin mathsize 14px style lambda to the power of apostrophe equals.... ? end style 

Jawab :

Untuk menyelesaikan soal ini kita gunakan rumus efek Compton :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell lambda to the power of apostrophe minus lambda end cell equals cell fraction numerator h over denominator m c end fraction open parentheses 1 minus cos open parentheses theta close parentheses close parentheses end cell row cell lambda to the power of apostrophe minus lambda end cell equals cell fraction numerator 6 comma 6 cross times 10 to the power of negative 34 end exponent over denominator 9 comma 1 cross times 10 to the power of negative 31 end exponent cross times 3 cross times 10 to the power of 8 end fraction open parentheses 1 minus cos open parentheses 15 degree close parentheses close parentheses end cell row cell lambda to the power of apostrophe minus lambda end cell equals cell open parentheses 0 comma 242 cross times 10 to the power of negative 11 end exponent close parentheses open parentheses 1 minus cos open parentheses 15 degree close parentheses close parentheses end cell row cell lambda to the power of apostrophe minus lambda end cell equals cell open parentheses 2 comma 42 cross times 10 to the power of negative 12 end exponent close parentheses open parentheses 1 minus 0 comma 96 close parentheses end cell row cell lambda to the power of apostrophe minus lambda end cell equals cell open parentheses 2 comma 42 cross times 10 to the power of negative 12 end exponent close parentheses open parentheses 0 comma 04 close parentheses end cell row cell lambda to the power of apostrophe minus lambda end cell equals cell 0 comma 0968 cross times 10 to the power of negative 12 end exponent end cell row cell lambda to the power of apostrophe minus 0 comma 4 cross times 10 to the power of negative 12 end exponent end cell equals cell 0 comma 0968 cross times 10 to the power of negative 12 end exponent end cell row cell lambda to the power of apostrophe end cell equals cell 0 comma 0968 cross times 10 to the power of negative 12 end exponent plus 0 comma 4 cross times 10 to the power of negative 12 end exponent end cell row cell lambda to the power of apostrophe end cell equals cell 0 comma 0968 cross times 10 to the power of negative 12 end exponent plus 0 comma 4 cross times 10 to the power of negative 12 end exponent end cell row cell lambda to the power of apostrophe end cell equals cell 0 comma 4968 cross times 10 to the power of negative 12 end exponent space straight m end cell end table end style 

Jadi, jawabannya begin mathsize 14px style bold 0 bold comma bold 04968 bold cross times bold 10 to the power of bold minus bold 12 end exponent bold space bold m end style.

1rb+

5.0 (2 rating)

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