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Reaksi pada suhu 30 degree C 0,5 mol gas P Cl subscript 5 dibiarkan terurai menurut reaksi:

P Cl subscript 5 open parentheses italic g close parentheses equilibrium P Cl subscript 3 open parentheses italic g close parentheses and Cl subscript 2 open parentheses italic g close parentheses 

Jika tetapan gas R=0,082, tekanan total gas pada keadaan setimbang adalah 2,4 atm dan derajat disosisasi 70%, maka tentukanlah:

a. Tekanan parsial masing-masing gas pada keadaan setimbang?

b. Harga K subscript italic p dan K subscript italic c 

F. Krisna

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Pembahasan

Pada reaksi: P Cl subscript 5 open parentheses italic g close parentheses equilibrium P Cl subscript 3 open parentheses italic g close parentheses and Cl subscript 2 open parentheses italic g close parentheses merupakan reaksi homogen dengan fase gas sehingga memiliki nilai  K subscript italic p dan K subscript italic c.

Derajat disosisasi open parentheses alpha close parentheses = 70% = 0,7 

table attributes columnalign right center left columnspacing 0px end attributes row alpha equals cell fraction numerator mol space bereaksi over denominator mol space mula bond mula end fraction end cell row cell 0 comma 7 end cell equals cell fraction numerator mol space bereaksi over denominator 0 comma 5 end fraction end cell row cell mol space bereaksi end cell equals cell 0 comma 7 cross times 0 comma 5 end cell row blank equals cell 0 comma 035 space mol end cell row blank blank blank end table 

 

a. Tekanan parsial 

table attributes columnalign right center left columnspacing 0px end attributes row cell italic p P Cl subscript 5 end cell equals cell fraction numerator mol space P Cl subscript 5 over denominator mol space total end fraction cross times italic p total end cell row blank equals cell fraction numerator 0 comma 15 over denominator 0 comma 85 end fraction cross times 2 comma 4 space atm end cell row blank equals cell 0 comma 423 space atm end cell row blank blank blank row cell italic p P Cl subscript 3 end cell equals cell fraction numerator mol space P Cl subscript 3 over denominator mol space total end fraction cross times italic p total end cell row blank equals cell fraction numerator 0 comma 35 over denominator 0 comma 85 end fraction cross times 2 comma 4 space atm end cell row blank equals cell 0 comma 988 space atm end cell row blank blank blank row cell italic p Cl 2 end cell equals cell fraction numerator mol space Cl subscript 2 over denominator mol space total end fraction cross times italic p total end cell row blank equals cell fraction numerator 0 comma 35 over denominator 0 comma 85 end fraction cross times 2 comma 4 space atm end cell row blank equals cell 0 comma 988 space atm end cell end table 

b. Harga  K subscript italic p dan K subscript italic c :

K subscript italic p
table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript italic p end cell equals cell fraction numerator left parenthesis italic p P Cl subscript 3 right parenthesis left parenthesis italic p Cl subscript 2 right parenthesis over denominator left parenthesis italic p P Cl subscript 5 right parenthesis end fraction end cell row blank equals cell fraction numerator left parenthesis 0 comma 988 right parenthesis left parenthesis 0 comma 988 right parenthesis over denominator left parenthesis 0 comma 423 right parenthesis end fraction end cell row blank equals cell 2 comma 3 space end cell end table 
 

K subscript italic c
table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript italic p end cell equals cell K subscript italic c open parentheses RT close parentheses to the power of increment n end exponent space end cell row cell 2 comma 3 end cell equals cell K subscript italic c left parenthesis 0 comma 082 cross times 303 K right parenthesis to the power of 2 minus sign 1 end exponent end cell row cell space K subscript italic c end cell equals cell fraction numerator 2 comma 3 over denominator 0 comma 082 cross times 303 end fraction space equals 0 comma 092 space end cell end table 

R: tetapan gas
T: suhu (K)

Jadi, jawaban yang benar adalah sesuai penjelasan di atas.  

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