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Reaksi brominasi aseton berlangsung sebagai berikut. CH 3 ​ COCH 3 ​ + Br 2 ​ → CH 3 ​ COCH 2 ​ Br + H + + Br − Untuk menentukan laju reaksinya, diperoleh data (konsentrasi mula-mula, M) sebagai berikut. Persamaan laju brominasi berdasarkan data di atas adalah ...

Reaksi brominasi aseton berlangsung sebagai berikut.

 

Untuk menentukan laju reaksinya, diperoleh data (konsentrasi mula-mula, M) sebagai berikut.
 


 

Persamaan laju brominasi berdasarkan data di atas adalah ...space space 

  1. v equals italic k open square brackets C H subscript 3 C O C H subscript 3 close square brackets open square brackets Br subscript 2 close square brackets open square brackets H to the power of plus sign close square brackets   
  2. v equals italic k open square brackets C H subscript 3 C O C H subscript 3 close square brackets open square brackets H to the power of plus sign close square brackets   

  3. v equals italic k open square brackets C H subscript 3 C O C H subscript 3 close square brackets open square brackets Br subscript 2 close square brackets   

  4. v equals italic k open square brackets C H subscript 3 C O C H subscript 3 close square brackets open square brackets Br subscript 2 close square brackets open square brackets H to the power of plus sign close square brackets to the power of italic 2   

  5. v equals italic k open square brackets C H subscript 3 C O C H subscript 3 close square brackets open square brackets H to the power of plus sign close square brackets to the power of italic 2   

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B. Rohmawati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.

jawaban yang benar adalah B.space 

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Pembahasan

Misal laju reaksinya adalah: Pada bercobaan 1 dan 2: sama dan beda maka: Jadi orde reaksi terhadap adalah 0. Pada bercobaan 2dan 3 sama dan beda maka: Jadi orde reaksi terhadap adalah 1. Untuk mendapatkan orde reaksi terhadap kita tinggal memasukan ke persamaan 1 dan 2. Jadi orde reaksi terhadap adalah 1 Pada perhitungan di atas kita telah menemukan nilai x=1, y=0 dan z=1, maka persamaan laju reaksinya adalah: Oleh karena itu, jawaban yang benar adalah B.

Misal laju reaksinya adalah: v double bond k open square brackets C H subscript 3 C O C H subscript 3 close square brackets to the power of x open square brackets Br subscript 2 close square brackets to the power of y open square brackets H to the power of plus sign close square brackets to the power of z 

  • Pada bercobaan 1 dan 2: open square brackets C H subscript 3 C O C H subscript 3 close square brackets space open square brackets H to the power of plus sign close square brackets  sama dan open square brackets Br subscript 2 close square brackets beda maka:
    table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 1 over v subscript 2 end cell equals cell fraction numerator k open square brackets C H subscript 3 C O C H subscript 3 close square brackets subscript 1 superscript x open square brackets Br subscript 2 close square brackets subscript 1 superscript y open square brackets H to the power of plus sign close square brackets subscript 1 superscript z over denominator k open square brackets C H subscript 3 C O C H subscript 3 close square brackets subscript 2 superscript x open square brackets Br subscript 2 close square brackets subscript 2 superscript y open square brackets H to the power of plus sign close square brackets subscript 2 superscript z end fraction end cell row cell fraction numerator 0 comma 57 over denominator 0 comma 57 end fraction end cell equals cell fraction numerator k open square brackets 0 comma 30 close square brackets subscript 1 superscript x open square brackets 0 comma 05 close square brackets subscript 1 superscript y open square brackets 0 comma 05 close square brackets subscript 1 superscript z over denominator k open square brackets 0 comma 30 close square brackets subscript 2 superscript x open square brackets 0 comma 10 close square brackets subscript 2 superscript y open square brackets 0 comma 05 close square brackets subscript 2 superscript z end fraction end cell row cell fraction numerator 0 comma 57 over denominator 0 comma 57 end fraction end cell equals cell open parentheses fraction numerator 0 comma 05 over denominator 0 comma 10 end fraction close parentheses to the power of y end cell row 1 equals cell open parentheses 1 half close parentheses to the power of y end cell row y equals 0 end table  
    Jadi orde reaksi terhadap open square brackets Br subscript 2 close square brackets adalah 0.
  • Pada bercobaan 2 dan 3 open square brackets C H subscript 3 C O C H subscript 3 close square brackets space open square brackets Br subscript 2 close square brackets sama dan open square brackets H to the power of plus sign close square brackets beda maka:
    table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 2 over v subscript 3 end cell equals cell fraction numerator k open square brackets C H subscript 3 C O C H subscript 3 close square brackets subscript 2 superscript x open square brackets Br subscript 2 close square brackets subscript 2 superscript y open square brackets H to the power of plus sign close square brackets subscript 2 superscript z over denominator k open square brackets C H subscript 3 C O C H subscript 3 close square brackets subscript 3 superscript x open square brackets Br subscript 2 close square brackets subscript 3 superscript y open square brackets H to the power of plus sign close square brackets subscript 3 superscript z end fraction end cell row cell fraction numerator 0 comma 57 over denominator 1 comma 2 end fraction end cell equals cell fraction numerator k open square brackets 0 comma 30 close square brackets subscript 1 superscript x open square brackets 0 comma 10 close square brackets subscript 1 superscript y open square brackets 0 comma 05 close square brackets subscript 1 superscript z over denominator k open square brackets 0 comma 30 close square brackets subscript 2 superscript x open square brackets 0 comma 10 close square brackets subscript 2 superscript y open square brackets 0 comma 10 close square brackets subscript 2 superscript z end fraction end cell row cell fraction numerator 0 comma 57 over denominator 1 comma 2 end fraction end cell equals cell open parentheses fraction numerator 0 comma 05 over denominator 0 comma 10 end fraction close parentheses to the power of italic z end cell row cell 1 half end cell equals cell open parentheses 1 half close parentheses to the power of 1 end cell row z equals 1 end table  
    Jadi orde reaksi terhadap open square brackets H to the power of plus sign close square brackets adalah 1.
  • Untuk mendapatkan orde reaksi terhadap open square brackets C H subscript 3 C O C H subscript 3 close square brackets kita tinggal memasukan ke persamaan 1 dan 2.
    table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 1 over v subscript 2 end cell equals cell fraction numerator k open square brackets C H subscript 3 C O C H subscript 3 close square brackets subscript 1 superscript x open square brackets Br subscript 2 close square brackets subscript 1 superscript y open square brackets H to the power of plus sign close square brackets subscript 1 superscript z over denominator k open square brackets C H subscript 3 C O C H subscript 3 close square brackets subscript 2 superscript x open square brackets Br subscript 2 close square brackets subscript 2 superscript y open square brackets H to the power of plus sign close square brackets subscript 2 superscript z end fraction end cell row y equals 0 row z equals 1 row cell fraction numerator 0 comma 57 over denominator 0 comma 57 end fraction end cell equals cell fraction numerator k open square brackets 0 comma 30 close square brackets subscript 1 superscript x open square brackets 0 comma 05 close square brackets subscript 1 superscript 0 open square brackets 0 comma 05 close square brackets subscript 1 superscript 1 over denominator k open square brackets 0 comma 30 close square brackets subscript 2 superscript x open square brackets 0 comma 10 close square brackets subscript 2 superscript 0 open square brackets 0 comma 05 close square brackets subscript 2 superscript 1 end fraction end cell row cell fraction numerator 0 comma 57 over denominator 0 comma 57 end fraction end cell equals cell open parentheses fraction numerator 0 comma 30 over denominator 0 comma 30 end fraction close parentheses to the power of x end cell row 1 equals cell open parentheses 1 close parentheses to the power of x end cell row x equals 1 end table 
    Jadi orde reaksi terhadap adalah 1
  • Pada perhitungan di atas kita telah menemukan nilai x=1, y=0 dan z=1, maka persamaan laju reaksinya adalah:
    v double bond k open square brackets C H subscript 3 C O C H subscript 3 close square brackets to the power of 1 open square brackets Br subscript 2 close square brackets to the power of 0 open square brackets H to the power of plus sign close square brackets to the power of 1 
    italic v bold equals italic k begin bold style open square brackets C H subscript 3 C O C H subscript 3 close square brackets end style to the power of bold 1 begin bold style open square brackets H to the power of plus sign close square brackets end style to the power of bold 1 

Oleh karena itu, jawaban yang benar adalah B.space 

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Berikut ini merupakan data percobaan dari reaksi: A+ B → produk. ​ Berdasarkan data tersebut, tentukanlah orde untuk masing-masing pereaksi, hukum laju reaksi, dan nilai tetapan laju reaksinya.

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