Roboguru

Perhatikan gambar di bawah! Luas bangun adalah

Pertanyaan

Perhatikan gambar di bawah!



Luas bangun text ABCDEF  end textadalah ....

  1. 318 space text cm end text squared space

  2. 278 space text cm end text squared space

  3. 258 space text cm end text squared space

  4. 243 space text cm end text squared space

Pembahasan Soal:

Bangun pada soal terdiri dari jajargenjang dan layang-layang. Diketahui text OF end text equals 8 space text cm dan EF end text equals 17 space text cm, end text maka

table attributes columnalign right center left columnspacing 0px end attributes row cell text OE end text squared end cell equals cell text EF end text squared minus text OF end text squared end cell row cell text OE end text squared end cell equals cell 17 squared minus 8 squared end cell row cell text OE end text squared end cell equals cell 289 minus 64 end cell row cell text OE end text squared end cell equals 225 row cell text OE end text end cell equals cell plus-or-minus square root of 225 end cell row cell text OE end text end cell equals cell plus-or-minus 15 text  cm end text end cell end table


Karena table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell text OE  end text end cell end tablemerupakan ukuran panjang maka nilai yang tepat adalah table attributes columnalign right center left columnspacing 0px end attributes row cell text OE end text end cell equals cell 15 text  cm. end text end cell end table 

Diketahui text AD end text equals text BC end text space equals 10 space text cm dan OF end text equals 8 space text cm, end text maka

table attributes columnalign right center left columnspacing 0px end attributes row cell text OA end text squared end cell equals cell text AF end text squared minus text OF end text squared end cell row cell text OA end text squared end cell equals cell 10 squared minus 8 squared end cell row cell text OA end text squared end cell equals cell 100 minus 64 end cell row cell text OF end text squared end cell equals 36 row cell text OA end text end cell equals cell plus-or-minus square root of 36 end cell row cell text OA end text end cell equals cell plus-or-minus 6 text  cm end text end cell end table


Karena table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell text OA  end text end cell end tablemerupakan ukuran panjang maka nilai yang tepat adalah table attributes columnalign right center left columnspacing 0px end attributes row cell text OA end text end cell equals cell 6 text  cm. end text end cell end table

 table attributes columnalign right center left columnspacing 0px end attributes row cell text OE end text end cell equals cell 15 text  cm  end text end cell end tabledan table attributes columnalign right center left columnspacing 0px end attributes row cell text OA end text end cell equals cell 6 text  cm, end text end cell end table maka table attributes columnalign right center left columnspacing 0px end attributes row cell text AE end text end cell equals cell 15 plus 6 equals 21 text  cm. end text end cell end table

Diketahui table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell text AB  end text end cell end tablemerupakan alas jajargenjang dengan panjang table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 15 text  cm  end text end cell end tabledan table attributes columnalign right center left columnspacing 0px end attributes row cell text OA end text end cell equals cell 6 text  cm  end text end cell end tablemerupakan tinggi jajargenjang, maka text L end text subscript text jajargenjang end text end subscript equals text a end text cross times text t end text equals 15 cross times 6 equals 90 space text cm end text squared.

Diketahui table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell text DF  end text end cell end tablemerupakan salah satu diagonal layang-layang table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell text ADEF, end text end cell end table maka berdasarkan karakteristik layang-layang didapat table attributes columnalign right center left columnspacing 0px end attributes row cell text OD end text end cell equals cell text OF end text equals 8 space text cm, end text end cell end table sehingga table attributes columnalign right center left columnspacing 0px end attributes row cell text DF end text end cell equals cell text OD end text plus text OF end text equals 8 plus 8 equals 16 space text cm. end text end cell end table table attributes columnalign right center left columnspacing 0px end attributes row cell text AE end text end cell equals cell 21 text  cm  end text end cell end tablemerupakan diagonal layang-layang yang lain, sehingga text L end text subscript text layang-layang end text end subscript equals 1 half cross times text d end text subscript 1 cross times text d end text subscript 2 equals 1 half cross times 16 cross times 21 equals 168 space text cm end text squared.

Maka luas bangun tersebut adalah text L end text subscript text jajargenjang end text end subscript plus text L end text subscript text layang-layang end text end subscript equals 90 plus 168 equals 258 space text cm end text squared.


Oleh karena itu, jawaban yang benar adalah C.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 02 Juni 2021

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved