Pertanyaan

Penjabaran dari bentuk a = − 6 ∑ − 2 2 a 4 − a adalah ....

Penjabaran dari bentuk $a = - 6 \sum - 2 \frac{4 - a}{2 a}$ adalah ....

$begin mathsize 14px style fraction numerator 4 minus 6 over denominator 2 left parenthesis 6 right parenthesis end fraction plus fraction numerator 4 minus 5 over denominator 2 left parenthesis 5 right parenthesis end fraction plus fraction numerator 4 minus 4 over denominator 2 left parenthesis 4 right parenthesis end fraction plus fraction numerator 4 minus 3 over denominator 2 left parenthesis 3 right parenthesis end fraction plus fraction numerator 4 minus 2 over denominator 2 left parenthesis 2 right parenthesis end fraction end style$
$begin mathsize 14px style fraction numerator 4 minus 6 over denominator 2 left parenthesis negative 6 right parenthesis end fraction plus fraction numerator 4 minus 5 over denominator 2 left parenthesis negative 5 right parenthesis end fraction plus fraction numerator 4 minus 4 over denominator 2 left parenthesis negative 4 right parenthesis end fraction plus fraction numerator 4 minus 3 over denominator 2 left parenthesis negative 3 right parenthesis end fraction plus fraction numerator 4 minus 2 over denominator 2 left parenthesis negative 2 right parenthesis end fraction end style$
$begin mathsize 14px style fraction numerator 4 minus left parenthesis negative 6 right parenthesis over denominator negative 6 end fraction plus fraction numerator 4 minus left parenthesis negative 5 right parenthesis over denominator negative 5 end fraction plus fraction numerator 4 minus left parenthesis negative 4 right parenthesis over denominator negative 4 end fraction plus fraction numerator 4 minus left parenthesis negative 3 right parenthesis over denominator negative 3 end fraction plus fraction numerator 4 minus left parenthesis negative 2 right parenthesis over denominator negative 2 end fraction end style$
$begin mathsize 14px style fraction numerator 4 minus left parenthesis negative 6 right parenthesis over denominator 2 left parenthesis 6 right parenthesis end fraction plus fraction numerator 4 minus left parenthesis negative 5 right parenthesis over denominator 2 left parenthesis 5 right parenthesis end fraction plus fraction numerator 4 minus left parenthesis negative 4 right parenthesis over denominator 2 left parenthesis 4 right parenthesis end fraction plus fraction numerator 4 minus left parenthesis negative 3 right parenthesis over denominator 2 left parenthesis 3 right parenthesis end fraction plus fraction numerator 4 minus left parenthesis negative 2 right parenthesis over denominator 2 left parenthesis 2 right parenthesis end fraction end style$
$begin mathsize 14px style fraction numerator 4 minus left parenthesis negative 6 right parenthesis over denominator 2 left parenthesis negative 6 right parenthesis end fraction plus fraction numerator 4 minus left parenthesis negative 5 right parenthesis over denominator 2 left parenthesis negative 5 right parenthesis end fraction plus fraction numerator 4 minus left parenthesis negative 4 right parenthesis over denominator 2 left parenthesis negative 4 right parenthesis end fraction plus fraction numerator 4 minus left parenthesis negative 3 right parenthesis over denominator 2 left parenthesis negative 3 right parenthesis end fraction plus fraction numerator 4 minus left parenthesis negative 2 right parenthesis over denominator 2 left parenthesis negative 2 right parenthesis end fraction end style$

N. Syafriah

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

Pembahasan

Jumlahkan semua dimulai dari sampai , didapat Dengan demikian, penjabaran dari bentuk adalah 2 ( − 6 ) 4 − ( − 6 ) + 2 ( − 5 ) 4 − ( − 5 ) + 2 ( − 4 ) 4 − ( − 4 ) + 2 ( − 3 ) 4 − ( − 3 ) + 2 ( − 2 ) 4 − ( − 2 ) . Jadi, jawaban yang tepat adalah E.

Jumlahkan semua $begin mathsize 14px style fraction numerator 4 minus a over denominator 2 a end fraction end style$ dimulai dari a equals negative 6 sampai a equals negative 2 , didapat

$begin mathsize 12px style table attributes columnalign right center left columnspacing 0px end attributes row cell sum from a equals negative 6 to negative 2 of fraction numerator 4 minus a over denominator 2 a end fraction end cell equals cell fraction numerator 4 minus open parentheses negative 6 close parentheses over denominator 2 open parentheses negative 6 close parentheses end fraction plus fraction numerator 4 minus open parentheses negative 5 close parentheses over denominator 2 open parentheses negative 5 close parentheses end fraction plus fraction numerator 4 minus open parentheses negative 4 close parentheses over denominator 2 open parentheses negative 4 close parentheses end fraction end cell row blank blank cell plus fraction numerator 4 minus open parentheses negative 3 close parentheses over denominator 2 open parentheses negative 3 close parentheses end fraction plus fraction numerator 4 minus open parentheses negative 2 close parentheses over denominator 2 open parentheses negative 2 close parentheses end fraction end cell end table end style$

Dengan demikian, penjabaran dari bentuk $begin mathsize 14px style sum from a equals negative 6 to negative 2 of fraction numerator 4 minus a over denominator 2 a end fraction end style$ adalah $\frac{4 - ( - 6 )}{2 ( - 6 )} + \frac{4 - ( - 5 )}{2 ( - 5 )} + \frac{4 - ( - 4 )}{2 ( - 4 )} + \frac{4 - ( - 3 )}{2 ( - 3 )} + \frac{4 - ( - 2 )}{2 ( - 2 )} .$