Pada reaksi: Menurut reaksi diatas bagan sel v...

Pada reaksi:

$begin mathsize 14px style Ni open parentheses italic s close parentheses and 2 Ag N O subscript 3 left parenthesis italic a italic q right parenthesis yields Ni open parentheses N O subscript 3 close parentheses subscript 2 left parenthesis italic a italic q right parenthesis plus 2 Ag open parentheses italic s close parentheses space end style$

Menurut reaksi diatas bagan sel volta dapat dituliskan dengan ...

$begin mathsize 14px style Ni to the power of 2 plus sign space I space Ni parallel to Ag space I space Ag to the power of plus sign end style$
$begin mathsize 14px style Ag space I space Ag to the power of plus space end exponent parallel to Ni to the power of 2 plus sign space I space Ni end style$
$begin mathsize 14px style Ni space I space Ni to the power of 2 plus sign parallel to Ag to the power of plus sign space I space Ag end style$
$begin mathsize 14px style Ni space I space Ag to the power of plus sign parallel to Ni to the power of 2 plus sign I space Ag end style$
$begin mathsize 14px style Ag space I space Ni to the power of 2 plus sign parallel to Ag to the power of plus sign I space Ni end style$

Jawaban:

Pada sel volta di katoda terjadi reaksi reduksi sedangkan pada anoda terjadi reaksi oksidasi.

biloks Ni = 0 (unsur bebas)

menentukan biloks dalam AgNO₃:

$Error converting from MathML to accessible text.$

menentukan biloks dalam Ni(NO₃)₂ :

$begin mathsize 14px style Ni open parentheses N O subscript 3 close parentheses subscript 2 yields Ni to the power of 2 plus sign plus 2 N O subscript 3 to the power of minus sign biloks space Ni space equals space plus 2 biloks space N plus left parenthesis 3 cross times biloks space O right parenthesis equals minus sign 1 biloks space N plus left parenthesis 3 cross times left parenthesis minus sign 2 right parenthesis right parenthesis equals minus sign 1 biloks space N plus left parenthesis minus sign 6 right parenthesis equals minus sign 1 biloks space N equals minus sign 1 plus 6 biloks space N equals plus 5 end style$

biloks Ag = 0(unsur bebas)

sehingga :

Anoda: reduksi (Ag)

katoda:oksidasi (Ni)

notasi sel :

$begin mathsize 14px style Anoda parallel to Katoda Ag space I space Ag to the power of plus sign parallel to Ni to the power of 2 plus sign I Ni end style$

Jadi, jawaban benar B.

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Download di Google Play

Download di Appstore

Produk Ruangguru

Produk Lainnya

Bantuan & Panduan

Hubungi Kami

081578200000

[email protected]

02140008000

Ikuti Kami

Instagram

Facebook

Twitter

Youtube