Roboguru

Pada reaksi:   Menurut reaksi diatas bagan sel v...

Pada reaksi:

begin mathsize 14px style Ni open parentheses italic s close parentheses and 2 Ag N O subscript 3 left parenthesis italic a italic q right parenthesis yields Ni open parentheses N O subscript 3 close parentheses subscript 2 left parenthesis italic a italic q right parenthesis plus 2 Ag open parentheses italic s close parentheses space end style 

Menurut reaksi diatas bagan sel volta dapat dituliskan dengan ...

  1. begin mathsize 14px style Ni to the power of 2 plus sign space I space Ni parallel to Ag space I space Ag to the power of plus sign end style 

  2. begin mathsize 14px style Ag space I space Ag to the power of plus space end exponent parallel to Ni to the power of 2 plus sign space I space Ni end style 

  3. begin mathsize 14px style Ni space I space Ni to the power of 2 plus sign parallel to Ag to the power of plus sign space I space Ag end style 

  4. begin mathsize 14px style Ni space I space Ag to the power of plus sign parallel to Ni to the power of 2 plus sign I space Ag end style 

  5. begin mathsize 14px style Ag space I space Ni to the power of 2 plus sign parallel to Ag to the power of plus sign I space Ni end style 

Jawaban:

Pada sel volta di katoda terjadi reaksi reduksi sedangkan pada anoda terjadi reaksi oksidasi.

biloks Ni = 0 (unsur bebas)

menentukan biloks dalam AgNO3:

Error converting from MathML to accessible text.  

menentukan biloks dalam Ni(NO3)2 :

begin mathsize 14px style Ni open parentheses N O subscript 3 close parentheses subscript 2 yields Ni to the power of 2 plus sign plus 2 N O subscript 3 to the power of minus sign biloks space Ni space equals space plus 2 biloks space N plus left parenthesis 3 cross times biloks space O right parenthesis equals minus sign 1 biloks space N plus left parenthesis 3 cross times left parenthesis minus sign 2 right parenthesis right parenthesis equals minus sign 1 biloks space N plus left parenthesis minus sign 6 right parenthesis equals minus sign 1 biloks space N equals minus sign 1 plus 6 biloks space N equals plus 5 end style 

biloks Ag = 0(unsur bebas)

sehingga :

Anoda: reduksi (Ag)

katoda:oksidasi (Ni)

notasi sel :

begin mathsize 14px style Anoda parallel to Katoda Ag space I space Ag to the power of plus sign parallel to Ni to the power of 2 plus sign I Ni end style 

Jadi, jawaban benar B.

 

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