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Pada gambar di bawah, jika kawat PQ sejajar kawat ...

Pada gambar di bawah, jika kawat PQ sejajar kawat RS dan diketahui begin mathsize 14px style i subscript 1 equals 6 space straight A end style, jarak kedua kawat a = 20 cm, begin mathsize 14px style mu subscript 0 equals 4 pi cross times 10 to the power of negative 7 end exponent end style wb/Am, menghasilkan gaya per satuan panjang sebesar begin mathsize 14px style 4 comma 8 cross times 10 to the power of negative 5 end exponent end style N/m, maka besar kuat arus begin mathsize 14px style i subscript 2 end styleadalah ....space

  1. 8 A

  2. 6 A

  3. 2 A

  4. 10 A

  5. 4 A

Jawaban:

i subscript 1 equals 6 space straight A a equals 0 comma 2 space straight m mu subscript o equals 4 straight pi cross times 10 to the power of negative 7 space end exponent Wb divided by Am F over l equals 4 comma 8 cross times 10 to the power of negative 5 end exponent space straight N divided by straight m Ditanya colon space i subscript 2 equals...

table attributes columnalign right center left columnspacing 0px end attributes row cell F over l end cell equals cell fraction numerator mu subscript o i subscript 1 i subscript 2 over denominator 2 πa end fraction end cell row cell 4 comma 8 cross times 10 to the power of negative 5 end exponent end cell equals cell fraction numerator open parentheses 4 straight pi cross times 10 to the power of negative 7 end exponent close parentheses open parentheses 6 close parentheses i subscript 2 over denominator 2 straight pi open parentheses 0 comma 2 close parentheses end fraction end cell row cell i subscript 2 end cell equals cell fraction numerator 4 comma 8 cross times 10 over denominator 6 end fraction end cell row blank equals cell 8 space straight A end cell end table

Jadi, pilihan jawaban yang tepat adalah A

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