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Pertanyaan

Nilai x → 0 lim ​ 3 − 9 + x 2 ​ 2 x 2 ​ = …

Nilai

  1. -18

  2. -12

  3. -9

  4. -6

  5. -3

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H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Pembahasan

limit as x rightwards arrow 0 of space fraction numerator 2 x squared over denominator 3 minus square root of 9 plus x squared end root end fraction equals  equals limit as x rightwards arrow 0 of space fraction numerator 2 x squared over denominator 3 minus left parenthesis 9 plus x squared right parenthesis to the power of begin display style 1 half end style end exponent end fraction  equals limit as x rightwards arrow 0 of space fraction numerator 4 x over denominator negative begin display style 1 half end style open parentheses 9 plus x squared close parentheses to the power of begin display style 1 half end style end exponent.2 x end fraction  equals limit as x rightwards arrow 0 of space fraction numerator 2 over denominator negative begin display style fraction numerator 1 over denominator 2 square root of 9 plus x squared end root end fraction end style end fraction  equals limit as x rightwards arrow 0 of space minus 4 square root of 9 plus x squared end root  equals negative 4 square root of 9 equals 4 left parenthesis 3 right parenthesis equals negative 12

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