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Pertanyaan

Nilai x → 4 lim ​ x 2 + 9 − 5 ​ x 2 − 16 ​ = …

Nilai

  1. -1

  2. negative 4 over 3

  3. negative 5 over 3

  4. -2

  5. negative 7 over 3

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H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Pembahasan

limit as x rightwards arrow 4 of space fraction numerator x squared minus 16 over denominator square root of x squared plus 9 minus 5 end root end fraction space  equals limit as x rightwards arrow 4 of space fraction numerator x squared minus 16 over denominator open parentheses x squared plus 9 close parentheses to the power of begin display style 1 half end style end exponent minus 5 end fraction  equals limit as x rightwards arrow 4 of space fraction numerator 2 x over denominator begin display style 1 half end style open parentheses x squared plus 9 close parentheses to the power of begin display style negative 1 half end style end exponent.2.5 end fraction  equals stack lim space with x rightwards arrow 4 below space fraction numerator 2 x over denominator begin display style fraction numerator 1 over denominator square root of x squared plus 9 end root end fraction end style minus 5 end fraction  equals fraction numerator 2 open parentheses 4 close parentheses over denominator begin display style fraction numerator 1 over denominator square root of 16 plus 9 end root minus 5 end fraction end style end fraction  equals fraction numerator 8 over denominator begin display style 1 fifth end style minus 8 end fraction  equals fraction numerator 8 over denominator begin display style fraction numerator 1 minus 25 over denominator 5 end fraction end style end fraction  equals 8 over 1. fraction numerator 5 over denominator negative 24 end fraction equals negative 5 over 3

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