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Pertanyaan

Nilai x → ∞ lim ​ 3 x 6 − 2 x 3 + 8 − 6 x 6 + 3 x 2 + 7 ​ = …

Nilai

  1. 2

  2. 1

  3. -1

  4. -2

  5. -3

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H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

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Pembahasan

space limit as x rightwards arrow infinity of space fraction numerator negative 6 x to the power of 6 plus 3 x squared plus 7 over denominator 3 x to the power of 6 minus 2 x cubed plus 8 end fraction  equals space limit as x rightwards arrow infinity of space fraction numerator begin display style fraction numerator negative 6 x to the power of 6 over denominator x to the power of 6 end fraction end style plus begin display style fraction numerator 3 x squared over denominator x to the power of 6 end fraction end style plus begin display style 7 over x to the power of 6 end style over denominator begin display style 3 over x to the power of 6 end style minus begin display style fraction numerator 2 x cubed over denominator x to the power of 6 end fraction end style plus begin display style 8 over x to the power of 6 end style end fraction  equals space limit as x rightwards arrow infinity of space fraction numerator negative 6 plus begin display style 3 over x to the power of 4 end style plus begin display style 7 over x to the power of 6 end style over denominator 3 minus 0 plus 0 plus 0 end fraction  equals fraction numerator negative 6 over denominator 3 end fraction equals negative 2

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x → ∞ lim ​ 2 x + 3 ​ − x − 2 ​ 2 x − 1 ​ + x + 1 ​ ​ = …

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