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Nilai x yang memenuhi pertidaksamaan ∣ 4 x − 2 ∣ > 14 adalah ....

Nilai  yang memenuhi pertidaksamaan  adalah ....

  1.  atau  

  2.  atau  

  3.  atau   

  4.  

  5.  

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F. Nur

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

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jawaban yang tepat adalah A.

jawaban yang tepat adalah A.

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Pembahasan

Ingat sifat pertidaksamaan nilai mutlak: ∣ f ( x ) ∣ ≤ a ↔ f ( x ) ≤ − a atau f ( x ) ≥ a Dengan menggunakan sifat pertidaksamaan nilai mutlak. ∣ 4 x − 2 ∣ > 14 ↔ 4 x − 2 < − 14 atau 4 x − 2 > 14 atau &14\\4x-2{\color[rgb]{1.0, 0.0, 0.0}+}{\color[rgb]{1.0, 0.0, 0.0}2}&>&14{\color[rgb]{1.0, 0.0, 0.0}+}{\color[rgb]{1.0, 0.0, 0.0}2}\\{\color[rgb]{0.1, 0.1, 0.1}4}{\color[rgb]{0.1, 0.1, 0.1}x}&{\color[rgb]{0.1, 0.1, 0.1}>}&{\color[rgb]{0.1, 0.1, 0.1}16}{\color[rgb]{0.1, 0.1, 0.1}\;}{\color[rgb]{0.1, 0.1, 0.1}\;}{\color[rgb]{1.0, 0.0, 0.0}(}{\color[rgb]{1.0, 0.0, 0.0}\mathrm bagi}{\color[rgb]{1.0, 0.0, 0.0}\;}{\color[rgb]{1.0, 0.0, 0.0}4}{\color[rgb]{1.0, 0.0, 0.0})}\\{\color[rgb]{0.1, 0.1, 0.1}x}&{\color[rgb]{0.1, 0.1, 0.1}>}&{\color[rgb]{0.1, 0.1, 0.1}4}\end{array}" data-mathml="«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnspacing=¨0px¨ columnalign=¨right center left¨»«mtr»«mtd»«mn»4«/mn»«mi»x«/mi»«mo»-«/mo»«mn»2«/mn»«/mtd»«mtd»«mo»§#62;«/mo»«/mtd»«mtd»«mn»14«/mn»«/mtd»«/mtr»«mtr»«mtd»«mn»4«/mn»«mi»x«/mi»«mo»-«/mo»«mn»2«/mn»«mo mathcolor=¨#FF0000¨»+«/mo»«mn mathcolor=¨#FF0000¨»2«/mn»«/mtd»«mtd»«mo»§#62;«/mo»«/mtd»«mtd»«mn»14«/mn»«mo mathcolor=¨#FF0000¨»+«/mo»«mn mathcolor=¨#FF0000¨»2«/mn»«/mtd»«/mtr»«mtr»«mtd»«mn mathcolor=¨#191919¨»4«/mn»«mi mathcolor=¨#191919¨»x«/mi»«/mtd»«mtd»«mo mathcolor=¨#191919¨»§#62;«/mo»«/mtd»«mtd»«mn mathcolor=¨#191919¨»16«/mn»«mo mathcolor=¨#191919¨»§#160;«/mo»«mo mathcolor=¨#191919¨»§#160;«/mo»«mo mathcolor=¨#FF0000¨»(«/mo»«mi mathcolor=¨#FF0000¨»bagi«/mi»«mo mathcolor=¨#FF0000¨»§#160;«/mo»«mn mathcolor=¨#FF0000¨»4«/mn»«mo mathcolor=¨#FF0000¨»)«/mo»«/mtd»«/mtr»«mtr»«mtd»«mi mathcolor=¨#191919¨»x«/mi»«/mtd»«mtd»«mo mathcolor=¨#191919¨»§#62;«/mo»«/mtd»«mtd»«mn mathcolor=¨#191919¨»4«/mn»«/mtd»«/mtr»«/mtable»«/math»" role="math" src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAKEAAABMCAYAAAAFi9fqAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAnZS4n9QAABfFJREFUeNrtnG9kXWccxyMiomJEk9wkN0uipqap6pu8iKoYNTMRVaqiZqLvaq9qVFVM7M1e1Uz1TV9URJSIqIgZEVFRE6YqJmZMzczEmJmJivDs++v9pTs9Ts45z7nnnHuee74fvu499z733Oec55vnz7nnm5YWQgghhBBCCCkhU5BpwPdOQlvQgT4+gDpDyj+FLiT4ntPQLPSiwOei1HRBuw068WvQBNSq2zeg5ZDy49BGAjMuQDMxjrGR56LUSANNF+TEixn3Y5TzmnHcYv/GoXNRGmQ4XIpooCe+hpbeYh3qz6A+w9AvFuWPzLgZ04ymznNBMhiGd6CTESe+Cv2gvVS7DpfvhTRymKJYhS4nOJZbMfdv6jwXJGXmoSsxe4nbqkfQ+QzqIouRRV0U2DCuvWC9PaHNuSApYtNbnYIOdRGRNhXocUjvGma+rZTmhEl7bpKBKYPogZ5B16C5DKYEK/poa76LKR5j0nIkBxN26iLkrG4/hMZS/M5Vz77jkNR8NKGjJpRFiFzH816Pk4n7NtTRgClB2t9DExJCCCGEEEIIIYQQQgghhBBLXMmAvMHEqC8KTEJb0IE+PjCOZUwyOs7C4VIGxLZx1qAJo/vH4w3jWMYko+MsHC5mQGI1TsBnWo1jGZOMj7MQOJsBSdg4w8axjElOx9nQYdiZDIg0RpRiNM6qKXjGpMHHmTtOZ0CMXW/SCS0aBzMmOR1nw3A5AxK7cVCoAj02jmZMMj7OQpoyiCJlQGxXjV3QinE4Y5LRcTplwqJlQGwbR+ZGTmdMMjpOZ0zofAYk6cQ+peNIxYQFO05CCCGEEEIIIYQQQggh5PUV6DvQXQfrfIet1xwGnDK1mz1crLtTd/dYMTAwMNXf35/KT1TYz1PszzpjUq1WT/f19c3i8y9CypzE+/dQ7nc8HuB7vsfzjy0asU1uVDX/35PYktdPc5a3k00FlZd6Qz+b2s/BzcPQ0FAXGnQ3LRPCKOMwx4atGVF+AeVnjqtHT09PJ97bhI5ujmhF+UvY/s6icSU38k1Sc+RkVrmbZ/e4ekn9TS1H1Dxo40+nZcIgM8pzi/oE1gM93hfQzTobeNnUIgJFNuECNB1iwknXAlihVCqVSRhlKazx8foTr4m051zv7u7utzTjZhwzhtTj+eDgYLXOBt7zxzj1bpkPdZj+29RCVEHD47bGQX+DrgeUmdF9yHd85jeRRex0Kaw8XjwB/dk0wzDMsSPzrLDGl4bHe6/zMaOjo+14vozXrO88xuduxeltQ0y4L/M/mTPKc/njQT3OWZrwMGiupndTv6sJu6+NL6qqC4Iz+vyimNX3vpjuW+gdNcmcrQl1GN45mq+a8AzNQbMMw/PQlajG14XLbdUjmNYqHyO9n87l6u0JD6EVWcDItvTE0kujTpfrNaFvW4y0YbPI0MXC+xFlokw4bzwZmrKY0ATpmGH7lJgAPdFEAvNtpTEnxOt7eGgLWFS9tDDhH2KyKHPghVe+7WE1yT9i5ACDHcQwapQJY91Uq0Gsvaa8TBOyIOjBe8/Q41yD5mzM51nJtqRgQum5h3099AmdKqS2MMFGFXrue+1H6HMZao/5zLZ3rqnDuvWcME75pluYRDW+XhZZR094Vss8hCnHIvaTyHwx/hjOyL7lUbZ7e3sr2F6UyzT1XqKBvtI5WYfO/y75yvwLnVNzTepnKp73P9W5ZKv2mksZmvC+qf27lOY3oSxC0MBr3mt9erF4e2RkpCOL74+aGsgfgPay+zo/PG/ZsO06f/NerJYh9qpem/sV+iDgc9ehv1R3oXv+IRHbN3Xl/BL6yP8vRNIwoUZSf2q6i9VlI6+f7cQsGeyzeX+2K6ERU70ZQOOiY57tT6AvU67zrKn9Bw9CAg1yVa/xvdIhWeaYbTwzhBBCCCGEEEIIIYQQ0iCSBp2OSDN0RUpK0qCTkHboitCM1kGnrEJXxP3hNZegU5zQFSkpeQSd4oauSInJOuhkE7oiJSXroJNN6IqUkLyDTuwJyVs0IuhEE5I35B10ognt+Q9pp4v9DcYv+AAAA/Z0RVh0TWF0aE1MADxtYXRoIHhtbG5zPSJodHRwOi8vd3d3LnczLm9yZy8xOTk4L01hdGgvTWF0aE1MIj48bXRhYmxlIGNvbHVtbmFsaWduPSJyaWdodCBjZW50ZXIgbGVmdCIgY29sdW1uc3BhY2luZz0iMHB4Ij48bXRyPjxtdGQ+PG1uPjQ8L21uPjxtaT54PC9taT48bW8+LTwvbW8+PG1uPjI8L21uPjwvbXRkPjxtdGQ+PG1vPiZndDs8L21vPjwvbXRkPjxtdGQ+PG1uPjE0PC9tbj48L210ZD48L210cj48bXRyPjxtdGQ+PG1uPjQ8L21uPjxtaT54PC9taT48bW8+LTwvbW8+PG1uPjI8L21uPjxtbyBtYXRoY29sb3I9IiNGRjAwMDAiPis8L21vPjxtbiBtYXRoY29sb3I9IiNGRjAwMDAiPjI8L21uPjwvbXRkPjxtdGQ+PG1vPiZndDs8L21vPjwvbXRkPjxtdGQ+PG1uPjE0PC9tbj48bW8gbWF0aGNvbG9yPSIjRkYwMDAwIj4rPC9tbz48bW4gbWF0aGNvbG9yPSIjRkYwMDAwIj4yPC9tbj48L210ZD48L210cj48bXRyPjxtdGQ+PG1uIG1hdGhjb2xvcj0iIzE5MTkxOSI+NDwvbW4+PG1pIG1hdGhjb2xvcj0iIzE5MTkxOSI+eDwvbWk+PC9tdGQ+PG10ZD48bW8gbWF0aGNvbG9yPSIjMTkxOTE5Ij4mZ3Q7PC9tbz48L210ZD48bXRkPjxtcm93PjxtbiBtYXRoY29sb3I9IiMxOTE5MTkiPjE2PC9tbj48bW8gbWF0aGNvbG9yPSIjMTkxOTE5Ij4mI3hBMDs8L21vPjxtbyBtYXRoY29sb3I9IiMxOTE5MTkiPiYjeEEwOzwvbW8+PG1vIG1hdGhjb2xvcj0iI0ZGMDAwMCI+KDwvbW8+PG1pIG1hdGhjb2xvcj0iI0ZGMDAwMCI+YmFnaTwvbWk+PG1vIG1hdGhjb2xvcj0iI0ZGMDAwMCI+JiN4QTA7PC9tbz48bW4gbWF0aGNvbG9yPSIjRkYwMDAwIj40PC9tbj48bW8gbWF0aGNvbG9yPSIjRkYwMDAwIj4pPC9tbz48L21yb3c+PC9tdGQ+PC9tdHI+PG10cj48bXRkPjxtaSBtYXRoY29sb3I9IiMxOTE5MTkiPng8L21pPjwvbXRkPjxtdGQ+PG1vIG1hdGhjb2xvcj0iIzE5MTkxOSI+Jmd0OzwvbW8+PC9tdGQ+PG10ZD48bW4gbWF0aGNvbG9yPSIjMTkxOTE5Ij40PC9tbj48L210ZD48L210cj48L210YWJsZT48L21hdGg+r8z0pwAAAABJRU5ErkJggg==" style="max-width: none;"> Diperolehhimpunan penyelesaian dari ∣ 4 x − 2 ∣ > 14 adalah x < − 3 atau x > 4 . Jadi, jawaban yang tepat adalah A.

Ingat sifat pertidaksamaan nilai mutlak:

   

Dengan menggunakan sifat pertidaksamaan nilai mutlak.

 

table attributes columnalign right center left columnspacing 0px end attributes row cell 4 x minus 2 end cell less than cell negative 14 end cell row cell 4 x minus 2 plus 2 end cell less than cell negative 14 plus 2 end cell row cell 4 x end cell less than cell negative 12 space left parenthesis bagi space 4 right parenthesis end cell row straight x less than cell negative 3 end cell end table 

atau 

table attributes columnalign right center left columnspacing 0px end attributes row cell 4 x minus 2 end cell greater than 14 row cell 4 x minus 2 plus 2 end cell greater than cell 14 plus 2 end cell row cell 4 x end cell greater than cell 16 space space left parenthesis bagi space 4 right parenthesis end cell row x greater than 4 end table 

Diperoleh himpunan penyelesaian dari  adalah  atau .

Jadi, jawaban yang tepat adalah A.

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