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Nilai dari adalah ....

Nilai dari begin mathsize 14px style limit as x rightwards arrow 2 of invisible function application fraction numerator open parentheses 3 minus square root of 7 plus x end root close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator x minus 2 end fraction end style adalah ....

  1. begin mathsize 14px style negative 4 over 3 end style 

  2. begin mathsize 14px style negative 2 over 3 end style 

  3. begin mathsize 14px style 2 over 3 end style 

  4. begin mathsize 14px style 4 over 3 end style 

  5. tidak ada

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Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

jawaban yang tepat adalah B.

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Pembahasan

Perhatikan bahwa Jadi, jawaban yang tepat adalah B.

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begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow 2 of invisible function application fraction numerator open parentheses 3 minus square root of 7 plus x end root close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator x minus 2 end fraction end cell row blank equals cell limit as x rightwards arrow 2 of invisible function application open parentheses fraction numerator open parentheses 3 minus square root of 7 plus x end root close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator x minus 2 end fraction times fraction numerator 3 plus square root of 7 plus x end root over denominator 3 plus square root of 7 plus x end root end fraction close parentheses end cell row blank equals cell limit as x rightwards arrow 2 of invisible function application fraction numerator open parentheses 3 minus square root of 7 plus x end root close parentheses open parentheses 3 plus square root of 7 plus x end root close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator open parentheses x minus 2 close parentheses open parentheses 3 plus square root of 7 plus x end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 2 of invisible function application fraction numerator open parentheses 9 minus open parentheses 7 plus x close parentheses close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator open parentheses x minus 2 close parentheses open parentheses 3 plus square root of 7 plus x end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 2 of invisible function application fraction numerator open parentheses 2 minus x close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator open parentheses x minus 2 close parentheses open parentheses 3 plus square root of 7 plus x end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 2 of invisible function application fraction numerator negative open parentheses x minus 2 close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator open parentheses x minus 2 close parentheses open parentheses 3 plus square root of 7 plus x end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 2 of invisible function application fraction numerator negative open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator 3 plus square root of 7 plus x end root end fraction end cell row blank equals cell fraction numerator negative open parentheses square root of 6 minus 2 end root plus 2 close parentheses over denominator 3 plus square root of 7 plus 2 end root end fraction end cell row blank equals cell fraction numerator negative open parentheses square root of 4 plus 2 close parentheses over denominator 3 plus square root of 9 end fraction end cell row blank equals cell fraction numerator negative open parentheses 2 plus 2 close parentheses over denominator 3 plus 3 end fraction end cell row blank equals cell negative 4 over 6 end cell row blank equals cell negative 2 over 3 end cell end table end style 

Jadi, jawaban yang tepat adalah B.

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