Pertanyaan

Nilai dari adalah ....

Nilai dari $begin mathsize 14px style limit as x rightwards arrow 2 of invisible function application fraction numerator open parentheses 3 minus square root of 7 plus x end root close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator x minus 2 end fraction end style$ adalah ....

tidak ada

8 dari 10 siswa nilainya naik

dengan paket belajar pilihan

Habis dalam

Klaim

F. Freelancer8

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

Perhatikan bahwa Jadi, jawaban yang tepat adalah B.

Perhatikan bahwa

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow 2 of invisible function application fraction numerator open parentheses 3 minus square root of 7 plus x end root close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator x minus 2 end fraction end cell row blank equals cell limit as x rightwards arrow 2 of invisible function application open parentheses fraction numerator open parentheses 3 minus square root of 7 plus x end root close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator x minus 2 end fraction times fraction numerator 3 plus square root of 7 plus x end root over denominator 3 plus square root of 7 plus x end root end fraction close parentheses end cell row blank equals cell limit as x rightwards arrow 2 of invisible function application fraction numerator open parentheses 3 minus square root of 7 plus x end root close parentheses open parentheses 3 plus square root of 7 plus x end root close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator open parentheses x minus 2 close parentheses open parentheses 3 plus square root of 7 plus x end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 2 of invisible function application fraction numerator open parentheses 9 minus open parentheses 7 plus x close parentheses close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator open parentheses x minus 2 close parentheses open parentheses 3 plus square root of 7 plus x end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 2 of invisible function application fraction numerator open parentheses 2 minus x close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator open parentheses x minus 2 close parentheses open parentheses 3 plus square root of 7 plus x end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 2 of invisible function application fraction numerator negative open parentheses x minus 2 close parentheses open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator open parentheses x minus 2 close parentheses open parentheses 3 plus square root of 7 plus x end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 2 of invisible function application fraction numerator negative open parentheses square root of 6 minus x end root plus 2 close parentheses over denominator 3 plus square root of 7 plus x end root end fraction end cell row blank equals cell fraction numerator negative open parentheses square root of 6 minus 2 end root plus 2 close parentheses over denominator 3 plus square root of 7 plus 2 end root end fraction end cell row blank equals cell fraction numerator negative open parentheses square root of 4 plus 2 close parentheses over denominator 3 plus square root of 9 end fraction end cell row blank equals cell fraction numerator negative open parentheses 2 plus 2 close parentheses over denominator 3 plus 3 end fraction end cell row blank equals cell negative 4 over 6 end cell row blank equals cell negative 2 over 3 end cell end table end style$

Jadi, jawaban yang tepat adalah B.