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Nilai dari adalah ....

Nilai dari cos squared invisible function application 1 to the power of degree plus cos squared invisible function application 2 to the power of degree plus cos squared invisible function application 3 to the power of degree plus midline horizontal ellipsis plus cos squared invisible function application 90 to the power of degree adalah ....

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Misalkan Perhatikan bahwa sehingga , maka nilai dari S dapat dituliskan sebagai berikut. Kemudian, untuk mencari nilai dari S diperlukan sifat trigonometri . Oleh karena itu, diperoleh bahwa . Akibatnya, untuk masing-masing nilai x berikut diperoleh beberapa persamaan berikut. Dengan demikian, diperoleh nilai x dapat dituliskan menjadi bentuk berikut. Kemudian, ingat bahwa sin 2 x + cos 2 x = 1 . Jumlahkan persamaan (i) dan (ii) sehingga diperoleh perhitungan berikut. Jadi, jawaban yang tepat adalah B.

Misalkan S equals cos squared invisible function application 1 to the power of degree plus cos squared invisible function application 2 to the power of degree plus cos squared invisible function application 3 to the power of degree plus midline horizontal ellipsis plus cos squared invisible function application 90 to the power of degree 

Perhatikan bahwa cos invisible function application 90 to the power of degree equals 0 sehingga cos squared invisible function application 90 to the power of degree equals 0, maka nilai dari  dapat dituliskan sebagai berikut.
 

S equals cos squared invisible function application 1 to the power of degree plus cos squared invisible function application 2 to the power of degree plus cos squared invisible function application 3 to the power of degree plus midline horizontal ellipsis plus cos squared invisible function application 89 to the power of degree midline horizontal ellipsis open parentheses i close parentheses

Kemudian, untuk mencari nilai dari  diperlukan sifat trigonometri cos invisible function application italic x equals sin invisible function application open parentheses 90 to the power of degree minus sign italic x close parentheses.

Oleh karena itu, diperoleh bahwa cos squared invisible function application italic x equals sin squared invisible function application open parentheses 90 to the power of degree minus sign italic x close parentheses.

Akibatnya, untuk masing-masing nilai  berikut diperoleh beberapa persamaan berikut.


table attributes columnalign right center left columnspacing 0px end attributes row cell cos squared invisible function application 1 to the power of degree end cell equals cell sin squared invisible function application 89 to the power of degree end cell row cell cos squared invisible function application 2 to the power of degree end cell equals cell sin squared invisible function application 88 to the power of degree end cell row cell cos squared invisible function application 3 to the power of degree end cell equals cell sin squared invisible function application 87 to the power of degree end cell row blank blank vertical ellipsis row cell cos squared invisible function application 45 to the power of degree end cell equals cell sin squared invisible function application 45 to the power of degree end cell row blank blank vertical ellipsis row cell cos squared invisible function application 89 to the power of degree end cell equals cell sin squared invisible function application 1 to the power of degree end cell end table
 

Dengan demikian, diperoleh nilai  dapat dituliskan menjadi bentuk berikut.
 

S equals sin squared invisible function application 1 to the power of degree plus sin squared invisible function application 2 to the power of degree plus sin squared invisible function application 3 to the power of degree plus midline horizontal ellipsis plus sin squared invisible function application 89 to the power of degree midline horizontal ellipsis open parentheses ii close parentheses 

Kemudian, ingat bahwa .

Jumlahkan persamaan (i) dan (ii) sehingga diperoleh perhitungan berikut.
 

table row cell S equals cos squared invisible function application 1 to the power of degree plus cos squared invisible function application 2 to the power of degree plus cos squared invisible function application 3 to the power of degree plus midline horizontal ellipsis plus cos squared invisible function application 89 to the power of degree end cell blank row cell S equals sin squared invisible function application 1 to the power of degree plus sin squared invisible function application 2 to the power of degree plus sin squared invisible function application 3 to the power of degree plus midline horizontal ellipsis plus sin squared invisible function application 89 to the power of degree end cell blank row cell negative sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign minus sign end cell plus row cell 2 S equals sin squared invisible function application 1 to the power of degree plus cos squared invisible function application 1 to the power of degree plus sin squared invisible function application 2 to the power of degree plus cos squared invisible function application 2 to the power of degree plus sin squared invisible function application 3 to the power of degree plus cos squared invisible function application 3 to the power of degree plus midline horizontal ellipsis plus sin squared invisible function application 89 to the power of degree plus cos squared invisible function application 89 to the power of degree end cell blank row cell 2 S equals 1 plus 1 plus 1 plus midline horizontal ellipsis plus end cell blank row cell 2 S equals 89 end cell blank row cell S equals 89 over 2 end cell blank row cell S equals 44 , 5 end cell blank end table

Jadi, jawaban yang tepat adalah B.

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