Nilai dari x→2lim​x−23−x+7​​ adalah ....

Pertanyaan

Nilai dari begin mathsize 14px style limit as x rightwards arrow 2 of fraction numerator 3 minus square root of x plus 7 end root over denominator x minus 2 end fraction end style adalah ....

E. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sebelas Maret

Jawaban terverifikasi

Jawaban

nilai limit as x rightwards arrow 2 of fraction numerator 3 minus square root of x plus 7 end root over denominator x minus 2 end fraction equals negative 1 third

Pembahasan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 2 of fraction numerator 3 minus square root of x plus 7 end root over denominator x minus 2 end fraction end cell equals cell limit as x rightwards arrow 2 of fraction numerator 3 minus square root of x plus 7 end root over denominator x minus 2 end fraction cross times fraction numerator 3 plus square root of x plus 7 end root over denominator 3 plus square root of x plus 7 end root end fraction end cell row blank equals cell limit as x rightwards arrow 2 of fraction numerator 3 squared minus left parenthesis x plus 7 right parenthesis over denominator left parenthesis x minus 2 right parenthesis cross times open parentheses square root of x plus 7 end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 2 of fraction numerator negative x plus 2 over denominator left parenthesis x minus 2 right parenthesis cross times open parentheses square root of x plus 7 end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 2 of fraction numerator negative 1 over denominator square root of x plus 7 end root end fraction end cell row blank equals cell fraction numerator negative 1 over denominator square root of 2 plus 7 end root end fraction end cell row blank equals cell negative 1 third end cell end table end style

Jadi nilai limit as x rightwards arrow 2 of fraction numerator 3 minus square root of x plus 7 end root over denominator x minus 2 end fraction equals negative 1 third

51

4.3 (3 rating)

Jois Butar butar

Pembahasan tidak lengkap

Pertanyaan serupa

limx→3​6x−9​−x2−2x+6​3x2−11​−3x+7​​= ....

74

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Fitur Roboguru

Topik Roboguru

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia