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Jika ....

Jika $begin mathsize 14px style limit as straight x rightwards arrow 3 of fraction numerator straight f open parentheses straight x close parentheses over denominator straight x minus 3 end fraction equals 5 comma space maka space limit as straight x rightwards arrow 3 of fraction numerator straight f open parentheses straight x close parentheses over denominator square root of 1 plus straight x end root minus 2 end fraction equals end style$ ....

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jawaban yang tepat adalah E.

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Perhatikan bahwa Jadi, jawaban yang tepat adalah E.

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$begin mathsize 14px style limit as straight x rightwards arrow 3 of fraction numerator straight f open parentheses straight x close parentheses over denominator square root of 1 plus straight x end root minus 2 end fraction equals limit as straight x rightwards arrow 3 of open parentheses fraction numerator straight f open parentheses straight x close parentheses over denominator square root of 1 plus straight x end root minus 2 end fraction times fraction numerator square root of 1 plus straight x end root plus 2 over denominator square root of 1 plus straight x end root plus 2 end fraction close parentheses equals limit as straight x rightwards arrow 3 of fraction numerator straight f open parentheses straight x close parentheses open parentheses square root of 1 plus straight x end root plus 2 close parentheses over denominator open parentheses square root of 1 plus straight x end root close parentheses squared minus 2 squared end fraction equals limit as straight x rightwards arrow 3 of fraction numerator straight f open parentheses straight x close parentheses open parentheses square root of 1 plus straight x end root plus 2 close parentheses over denominator open parentheses 1 plus straight x close parentheses minus 4 end fraction equals limit as straight x rightwards arrow 3 of fraction numerator straight f open parentheses straight x close parentheses open parentheses square root of 1 plus straight x end root plus 2 close parentheses over denominator straight x minus 3 end fraction equals limit as straight x rightwards arrow 3 of fraction numerator straight f open parentheses straight x close parentheses over denominator straight x minus 3 end fraction times limit as straight x rightwards arrow 3 of open parentheses square root of 1 plus straight x end root plus 2 close parentheses equals 5 open parentheses square root of 1 plus 3 end root plus 2 close parentheses equals 5 open parentheses square root of 4 plus 2 close parentheses equals 5 open parentheses 2 plus 2 close parentheses equals 5 open parentheses 4 close parentheses equals 20 end style$

Jadi, jawaban yang tepat adalah E.