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Nilai cosius sudut antara bidang BDE dan bidang BDG seperti terlihat pada gambar prisma segi-4 ABCD.EFGH beraturan berikut adalah...

Nilai cosius sudut antara bidang BDE dan bidang BDG seperti terlihat pada gambar prisma segi-4 ABCD.EFGH beraturan berikut adalah...

  1. 2 over 6

  2. 3 over 6

  3. 4 over 6

  4. 7 over 9

  5. 8 over 9

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Y. Endah

Master Teacher

Mahasiswa/Alumni Institut Teknologi Bandung

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P e r t a m a space b u a t space t i t i k space b a n t u a n comma space y a i t u space t i t i k space P space y a n g space m e m b a g i space d u a space g a r i s space B D comma space  s e h i n g g a space d i p e r o l e h space s e g i space t i g a space E P G. space  J a d i comma space cos i n u s space s u d u t space a n t a r a space B D E space d a n space B D G space a d a l a h space cos space angle E P G space space space  p a d a space s e g i space t i g a space E P G. space P e r h a t i k a n  A P space equals 1 half A C space equals space 1 half 4 square root of 2 equals 2 square root of 2  E P space equals space square root of A P squared plus A E squared end root  equals square root of left parenthesis 2 square root of 2 right parenthesis squared plus 8 squared end root  equals square root of 8 plus 64 end root  equals square root of 72  D e n g a n space c a r a space y a n g space s a m a space comma space d i p e r o l e h space E P equals G P equals square root of 72  cos space angle E P G space space equals fraction numerator E P squared plus G P squared minus E G squared over denominator 2 times E P times G P end fraction  equals fraction numerator left parenthesis square root of 72 right parenthesis squared plus left parenthesis square root of 72 right parenthesis squared minus left parenthesis 4 square root of 2 right parenthesis squared over denominator 2 left parenthesis square root of 72 right parenthesis left parenthesis square root of 72 right parenthesis end fraction  equals fraction numerator 72 plus 72 minus 32 over denominator 2 left parenthesis 72 right parenthesis end fraction  equals 112 over 144 equals 7 over 9    space space space space space space space space space space space space

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Dari sebuah bidang-:empat ABCD diketahui BC ⊥ BDdan AB tegak turus bidang BCD~ BC = BD = a 2 ​ dan AB = a, maka sudut antara bidang ACD dan bidang BCD sama dengan ...

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