Nilai x→−5lim​ x+51−x+6​​ adalah....

Pertanyaan

Nilai begin mathsize 14px style limit as x rightwards arrow negative 5 of space fraction numerator 1 minus square root of x plus 6 end root over denominator x plus 5 end fraction end style adalah....

  1. begin mathsize 14px style negative 1 fourth end style 

  2. begin mathsize 14px style negative 1 half end style 

  3. begin mathsize 14px style 1 end style 

  4. begin mathsize 14px style 2 end style 

  5. begin mathsize 14px style 4 end style 

L. Indah

Master Teacher

Mahasiswa/Alumni Universitas Siliwangi

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.

Pembahasan

Nilai limit pada soal di atas dapat dicari dengan cara mengalikannya dengan akar sekawan dari begin mathsize 14px style 1 minus square root of x plus 6 end root end style yaitu begin mathsize 14px style 1 plus square root of x plus 6 end root end style. Diperoleh

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow negative 5 of fraction numerator 1 minus square root of x plus 6 end root over denominator x plus 5 end fraction end cell equals cell limit as x rightwards arrow negative 5 of open parentheses fraction numerator 1 minus square root of x plus 6 end root over denominator x plus 5 end fraction times fraction numerator 1 plus square root of x plus 6 end root over denominator 1 plus square root of x plus 6 end root end fraction close parentheses end cell row blank equals cell limit as x rightwards arrow negative 5 of fraction numerator 1 minus left parenthesis x minus 6 right parenthesis over denominator open parentheses x plus 5 close parentheses open parentheses 1 plus square root of x plus 6 end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow negative 5 of fraction numerator negative left parenthesis x plus 5 right parenthesis over denominator open parentheses x plus 5 close parentheses open parentheses 1 plus square root of x plus 6 end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow negative 5 of open parentheses negative fraction numerator 1 over denominator 1 plus square root of x plus 6 end root end fraction close parentheses end cell row blank equals cell negative fraction numerator 1 over denominator 1 plus square root of negative 5 plus 6 end root end fraction end cell row blank equals cell negative 1 half end cell end table end style 
 

Dengan demikian, jawaban yang benar adalah B.

137

4.6 (11 rating)

Athina Rizka Akhmalia

Jawaban tidak sesuai Pembahasan tidak menjawab soal Pembahasan tidak lengkap Pembahasan terpotong

Faizal 1

Ini yang aku cari!

Pertanyaan serupa

Hitunglah nilai a dan b yang memenuhi kesamaan limit berikut. a. x→1lim​x−1x2+ax+b​=3

127

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Jawaban terverifikasi

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