Nilai x→21​lim​6x2−7x+22x2+5x−3​ adalah ....

Pertanyaan

Nilai begin mathsize 14px style limit as x rightwards arrow 1 half of fraction numerator 2 x squared plus 5 x minus 3 over denominator 6 x squared minus 7 x plus 2 end fraction end style adalah ....

  1. begin mathsize 14px style 7 end style 

  2. begin mathsize 14px style 5 end style 

  3. begin mathsize 14px style negative 3 end style 

  4. begin mathsize 14px style negative 5 end style 

  5. begin mathsize 14px style negative 7 end style 

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Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

Pembahasan

Pembahasan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 1 half of fraction numerator 2 x squared plus 5 x minus 3 over denominator 6 x squared minus 7 x plus 2 end fraction end cell equals cell limit as x rightwards arrow 1 half of fraction numerator left parenthesis 2 x minus 1 right parenthesis left parenthesis x plus 3 right parenthesis over denominator left parenthesis 2 x minus 1 right parenthesis left parenthesis 3 x minus 2 right parenthesis end fraction end cell row blank equals cell limit as x rightwards arrow 1 half of fraction numerator up diagonal strike left parenthesis 2 x minus 1 right parenthesis end strike left parenthesis x plus 3 right parenthesis over denominator up diagonal strike left parenthesis 2 x minus 1 end strike right parenthesis left parenthesis 3 x minus 2 right parenthesis end fraction end cell row blank equals cell limit as x rightwards arrow 1 half of fraction numerator x plus 3 over denominator 3 x minus 2 end fraction end cell row blank equals cell fraction numerator begin display style 1 half end style plus 3 over denominator 3 open parentheses begin display style 1 half end style close parentheses minus 2 end fraction end cell row blank equals cell fraction numerator open parentheses begin display style 1 half end style plus begin display style 6 over 2 end style close parentheses over denominator open parentheses begin display style 3 over 2 end style minus begin display style 4 over 2 end style close parentheses end fraction end cell row blank equals cell fraction numerator open parentheses begin display style 7 over 2 end style close parentheses over denominator open parentheses begin display style fraction numerator negative 1 over denominator 2 end fraction end style close parentheses end fraction end cell row blank equals cell negative 7 end cell end table end style 

Jadi, jawaban yang tepat adalah E.

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Diketahui x→1lim​x−1f(x)​=−2 dan x→3lim​x−3f(x)​=10. Jika f(x) merupakan fungsi berderajat 3 yang memenuhi kedua limit tersebut, tentukanlah rumus fungsi .

387

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Jawaban terverifikasi

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