Pertanyaan

Nilai ∫ − 1 2 ( x 2 4 − x 3 16 + 2 ) d x = ...

Nilai $\int_{- 1}^{2} (\frac{4}{x ^{2}} - \frac{16}{x ^{3}} + 2) d x =$ ...

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Jawaban terverifikasi

Jawaban

nilai dari adalah .

nilai dari integral subscript negative 1 end subscript superscript 2 open parentheses 4 over x squared minus 16 over x cubed plus 2 close parentheses space straight d x

integral subscript negative 1 end subscript superscript 2 open parentheses 4 over x squared minus 16 over x cubed plus 2 close parentheses space straight d x

adalah

Pembahasan

Jadi, nilai dari adalah .

$integral subscript negative 1 end subscript superscript 2 open parentheses 4 over x squared minus 16 over x cubed plus 2 close parentheses space straight d x equals integral subscript negative 1 end subscript superscript 2 open parentheses 4 x to the power of negative 2 end exponent minus 16 x to the power of negative 3 end exponent plus 2 close parentheses space straight d x equals open square brackets fraction numerator 1 over denominator negative 2 plus 1 end fraction 4 x to the power of negative 2 plus 1 end exponent minus fraction numerator 16 over denominator negative 2 end fraction x to the power of negative 3 plus 1 end exponent plus 2 x close square brackets subscript negative 1 end subscript superscript 2 equals open square brackets negative 4 x to the power of negative 1 end exponent plus 8 x to the power of negative 2 end exponent plus 2 x close square brackets subscript negative 1 end subscript superscript 2 equals open square brackets negative 4 over x plus 8 over x squared plus 2 x close square brackets subscript negative 1 end subscript superscript 2 equals open parentheses negative 4 over 2 plus 8 over 2 squared plus 2 open parentheses 2 close parentheses plus C close parentheses minus open parentheses negative fraction numerator 4 over denominator open parentheses negative 1 close parentheses end fraction plus 8 over open parentheses negative 1 close parentheses squared plus 2 open parentheses negative 1 close parentheses plus C close parentheses equals open parentheses negative 2 plus 2 plus 4 plus C close parentheses minus open parentheses 4 plus 8 minus 2 plus C close parentheses equals 4 minus 10 equals negative 6$

Jadi, nilai dari integral subscript negative 1 end subscript superscript 2 open parentheses 4 over x squared minus 16 over x cubed plus 2 close parentheses space straight d x adalah negative 6 .