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Pertanyaan

Muai volume benzena dan kayu masing-masing adalah begin mathsize 14px style 1 comma 2 cross times 10 to the power of negative 3 end exponent divided by degree straight C end style dan begin mathsize 14px style 1 comma 5 cross times 10 to the power of negative 4 end exponent divided by degree straight C end style. Jika massa jenis keduanya pada 0°C masing-masing adalah begin mathsize 14px style 8 comma 7 cross times 10 to the power of negative 2 end exponent space kg divided by straight m cubed end style dan begin mathsize 14px style 8 comma 5 cross times 10 to the power of negative 2 end exponent space kg divided by straight m cubed end style, maka pada suhu berapakah kayu tepat akan tenggelam dalam benzena?

R. Mutia

Master Teacher

Mahasiswa/Alumni Universitas Gadjah Mada

Jawaban terverifikasi

Jawaban

kayu akan tepat tenggelam dalam benzena pada suhu table attributes columnalign right center left columnspacing 0px end attributes row blank blank 22 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank comma end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 5 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank degree end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight C end table.

Pembahasan

Diketahui:

gamma subscript b equals 1 comma 2 cross times 10 to the power of negative 3 end exponent divided by degree straight C gamma subscript k equals 1 comma 5 cross times 10 to the power of negative 4 end exponent divided by degree straight C rho subscript B equals 8 comma 7 cross times 10 to the power of negative 2 end exponent space kg divided by straight m cubed rho subscript B equals 8 comma 5 cross times 10 to the power of negative 2 end exponent space kg divided by straight m cubed

Ditanya: T.

Penyelesaian:

Soal ini dapat dikerjakan menggunakan persamaan muai volume. Kayu akan tepat tenggelam apabila;

table attributes columnalign right center left columnspacing 0px end attributes row cell rho subscript k a y u end subscript end cell equals cell rho subscript b e n z e n a end subscript end cell row cell m subscript k over V subscript k end cell equals cell m subscript b over V subscript b end cell row cell fraction numerator m subscript k over denominator V subscript 0 subscript k end subscript open parentheses 1 plus gamma subscript k increment T close parentheses end fraction end cell equals cell fraction numerator m subscript b over denominator V subscript 0 subscript b end subscript open parentheses 1 plus gamma subscript b increment T close parentheses end fraction end cell row cell fraction numerator rho subscript 0 subscript k end subscript over denominator open parentheses 1 plus gamma subscript k increment T close parentheses end fraction end cell equals cell fraction numerator rho subscript 0 subscript b end subscript over denominator open parentheses 1 plus gamma subscript b increment T close parentheses end fraction end cell row cell fraction numerator 8 comma 5 cross times 10 to the power of negative 2 end exponent over denominator open parentheses 1 plus open parentheses 1 comma 5 cross times 10 to the power of negative 4 end exponent close parentheses open parentheses T minus 0 close parentheses close parentheses end fraction end cell equals cell fraction numerator 8 comma 7 cross times 10 to the power of negative 2 end exponent over denominator open parentheses 1 plus open parentheses 1 comma 2 cross times 10 to the power of negative 3 end exponent close parentheses open parentheses T minus 0 close parentheses close parentheses end fraction end cell row cell 8 comma 5 open parentheses 1 plus open parentheses 1 comma 2 cross times 10 to the power of negative 3 end exponent close parentheses T close parentheses end cell equals cell 8 comma 7 open parentheses 1 plus open parentheses 1 comma 5 cross times 10 to the power of negative 4 end exponent close parentheses T close parentheses end cell row cell 8 comma 5 plus 10 comma 2 cross times 10 to the power of negative 3 end exponent T end cell equals cell 8 comma 7 plus 1 comma 305 cross times 10 to the power of negative 3 end exponent T end cell row cell 10 comma 2 cross times 10 to the power of negative 3 end exponent T minus 1 comma 305 cross times 10 to the power of negative 3 end exponent T end cell equals cell 8 comma 7 minus 8 comma 5 end cell row cell 8 comma 895 cross times 10 to the power of negative 3 end exponent T end cell equals cell 0 comma 2 end cell row T equals cell fraction numerator 0 comma 2 over denominator 8 comma 895 cross times 10 to the power of negative 3 end exponent end fraction end cell row blank equals cell 22 comma 5 degree straight C end cell end table 

Dengan demikian, kayu akan tepat tenggelam dalam benzena pada suhu table attributes columnalign right center left columnspacing 0px end attributes row blank blank 22 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank comma end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 5 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank degree end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight C end table.

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