Roboguru

Membuat kurva titrasi 50 mL CH3COOH 0,05 M dengan NaOH 0,1 M. Ka CH3COOH = 1,8×10−5  Gunakan tabel berikut untuk menentukan titik dalam kurva.

Pertanyaan

Membuat kurva titrasi 50 mL CH3COOH 0,05 M dengan NaOH 0,1 M.

Ka CH3COOH = 1 comma 8 cross times 10 to the power of negative sign 5 end exponent 

Gunakan tabel berikut untuk menentukan titik dalam kurva. 

Pembahasan:

Untuk menentukan pH larutan dari titrasi larutan CH3COOH dan NaOH, dengan cara sebagai berikut :

a) pH CH3COOH sebelum ditambah NaOH

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of K subscript a cross times M end root end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of 1 comma 8 cross times 10 to the power of negative sign 5 end exponent cross times 0 comma 05 end root end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 3 cross times 10 to the power of negative sign 3 comma 5 end exponent end cell row pH equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row pH equals cell negative sign log space open parentheses 3 cross times 10 to the power of negative sign 3 comma 5 end exponent close parentheses end cell row pH equals cell 3 comma 5 minus sign log space 3 end cell row pH equals cell 3 comma 02 end cell end table 

b) pH larutan CH3COOH setelah ditambah NaOH sebanyak 10 mL

mol space C H subscript 3 C O O H double bond M cross times V equals 0 comma 05 cross times 50 equals 2 comma 5 space mmol mol space Na O H double bond M cross times V equals 0 comma 1 cross times 10 equals 1 space mmol 

Persamaan reaksi asam - basa :

Pada reaksi asam-basa diatas, mmol CH3COOH bersisa maka larutan yang terbentuk adalah larutan penyangga asam. Rumus untuk menentukan pH larutan penyangga asam :

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell K subscript a cross times fraction numerator mol space C H subscript 3 C O O H over denominator mol space C H subscript 3 C O O Na end fraction end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 1 comma 8 cross times 10 to the power of negative sign 5 end exponent cross times fraction numerator 1 comma 5 over denominator 1 end fraction end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 2 comma 7 cross times 10 to the power of negative sign 5 end exponent space M end cell row pH equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row cell space space space space end cell equals cell negative sign log space left parenthesis 2 comma 7 cross times 10 to the power of negative sign 5 end exponent right parenthesis end cell row pH equals cell 5 minus sign log space 2 comma 7 end cell row pH equals cell 4 comma 57 end cell end table  

c) pH larutan CH3COOH setelah ditambah NaOH sebanyak 20 mL.

mol space C H subscript 3 C O O H double bond M cross times V equals 0 comma 05 cross times 50 equals 2 comma 5 space mmol mol space Na O H double bond M cross times V equals 0 comma 1 cross times 20 equals 2 space mmol 

Persamaan reaksi asam - basa :

Pada reaksi asam-basa diatas, mmol CH3COOH bersisa maka larutan yang terbentuk adalah larutan penyangga asam. Rumus untuk menentukan pH larutan penyangga asam :

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell K subscript a cross times fraction numerator mol space C H subscript 3 C O O H over denominator mol space C H subscript 3 C O O Na end fraction end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 1 comma 8 cross times 10 to the power of negative sign 5 end exponent cross times fraction numerator 0 comma 5 over denominator 2 end fraction end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 4 comma 5 cross times 10 to the power of negative sign 6 end exponent space M end cell row pH equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row cell space space space space end cell equals cell negative sign log space left parenthesis 4 comma 5 cross times 10 to the power of negative sign 6 end exponent right parenthesis end cell row pH equals cell 6 minus sign log space 4 comma 5 end cell row pH equals cell 5 comma 35 end cell end table 

d) pH larutan CH3COOH setelah ditambah NaOH sebanyak 25 mL

mol space C H subscript 3 C O O H double bond M cross times V equals 0 comma 05 cross times 50 equals 2 comma 5 space mmol mol space Na O H double bond M cross times V equals 0 comma 1 cross times 25 equals 2 comma 5 space mmol 

Persamaan reaksi asam - basa :

 

Pada reaksi asam-basa diatas, mmol CH3COOH = mmol NaOH maka larutan yang terbentuk adalah hidrolisis garam yang bersifat basa. Rumus untuk menentukan pH larutan garamnya:

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of K subscript w over K subscript a cross times open square brackets C H subscript 3 C O O Na close square brackets end root end cell row cell open square brackets C H subscript 3 C O O Na close square brackets end cell equals cell fraction numerator mmol space sisa over denominator Vtotal end fraction equals fraction numerator 2 comma 5 over denominator 75 end fraction equals 1 over 30 M end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of fraction numerator 10 to the power of negative sign 14 end exponent over denominator 1 comma 8 cross times 10 to the power of negative sign 5 end exponent end fraction cross times 1 over 30 end root end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 4 comma 3 cross times 10 to the power of negative sign 6 end exponent space M end cell row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row cell space space space space space space space end cell equals cell negative sign log space open parentheses 4 comma 3 cross times 10 to the power of negative sign 6 end exponent close parentheses end cell row pOH equals cell 6 minus sign log space 4 comma 3 end cell row cell pH and pOH end cell equals 14 row pH equals cell 14 minus sign open parentheses 6 minus sign log space 4 comma 3 close parentheses end cell row pH equals cell 8 plus log space 4 comma 3 end cell row pH equals cell 8 comma 63 end cell end table  

e) pH larutan CH3COOH setelah ditambah NaOH sebanyak 30 mL

mol space C H subscript 3 C O O H double bond M cross times V equals 0 comma 05 cross times 50 equals 2 comma 5 space mmol mol space Na O H double bond M cross times V equals 0 comma 1 cross times 30 equals 3 space mmol 

Persamaan reaksi asam - basa :

Pada reaksi asam-basa diatas, mmol NaOH bersisa maka larutan yang terbentuk adalah basa kuat. Rumus untuk menentukan pH basa kuat :

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell M cross times b end cell row cell space space space space space space space end cell equals cell fraction numerator 0 comma 5 over denominator 80 end fraction cross times 1 equals 6 comma 25 cross times 10 to the power of negative sign 3 end exponent space M end cell row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row pOH equals cell negative sign log space open parentheses 6 comma 25 cross times 10 to the power of negative sign 3 end exponent close parentheses end cell row pOH equals cell 3 minus sign log space 6 comma 25 end cell row cell pH and pOH end cell equals 14 row pH equals cell 14 minus sign open parentheses 3 minus sign log space 6 comma 25 close parentheses end cell row pH equals cell 11 plus log space 6 comma 25 end cell row pH equals cell 11 comma 80 end cell end table  

Jadi, data titrasi 50 mL larutan CH3COOH 0,05 M dengan larutan NaOH 0,1 M sebagai berikut:

Jawaban terverifikasi

Dijawab oleh:

S. Oktasari

Mahasiswa/Alumni Universitas Padjadjaran

Terakhir diupdate 07 Oktober 2021

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

Tapi Roboguru masih mau belajar. Menurut kamu pembahasan kali ini sudah membantu, belum?

Membantu

Kurang Membantu

Apakah pembahasan ini membantu?

Belum menemukan yang kamu cari?

Post pertanyaanmu ke Tanya Jawab, yuk

Mau Bertanya

Pertanyaan serupa

Pada titrasi 25 mL larutan HCOOH 0,4 M (Ka​=1⋅10−5) dengan larutan Ca(OH)2​ 0,1 M. Tentukan: a. pH awal titrasi b. volume c. pH titik ekuivalen d. kurva titrasi

0

Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

Tapi Roboguru masih mau belajar. Menurut kamu pembahasan kali ini sudah membantu, belum?

Membantu

Kurang Membantu

Apakah pembahasan ini membantu?

Belum menemukan yang kamu cari?

Post pertanyaanmu ke Tanya Jawab, yuk

Mau Bertanya

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved