Pertanyaan

Matriks pencerminan terhadap garis y = m x adalah ...

Matriks pencerminan terhadap garis $y = m x$ adalah ...

$open parentheses table row cell fraction numerator 1 minus m squared over denominator 1 plus m squared end fraction end cell cell fraction numerator 2 m over denominator 1 plus m squared end fraction end cell row cell fraction numerator 2 m over denominator 1 plus m squared end fraction end cell cell fraction numerator negative 1 plus m squared over denominator 1 plus m squared end fraction end cell end table close parentheses$
$open parentheses table row cell fraction numerator 2 m over denominator 1 plus m squared end fraction end cell cell fraction numerator 1 minus m squared over denominator 1 plus m squared end fraction end cell row cell fraction numerator 1 minus m squared over denominator 1 plus m squared end fraction end cell cell fraction numerator negative 1 plus m squared over denominator 1 plus m squared end fraction end cell end table close parentheses$
$open parentheses table row cell fraction numerator 2 m over denominator 1 plus m squared end fraction end cell cell fraction numerator 1 minus m squared over denominator 1 plus m squared end fraction end cell row cell fraction numerator m squared minus 1 over denominator 1 plus m squared end fraction end cell cell fraction numerator negative 2 m over denominator 1 plus m squared end fraction end cell end table close parentheses$
$open parentheses table row cell fraction numerator m over denominator 1 plus m squared end fraction end cell cell fraction numerator 1 minus m squared over denominator 1 plus m squared end fraction end cell row cell fraction numerator m plus 1 over denominator 1 plus m squared end fraction end cell cell fraction numerator negative m over denominator 1 plus m squared end fraction end cell end table close parentheses$

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Habis dalam

Klaim

M. Iqbal

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah A.

Pembahasan

Ingat cara untuk menentukan peta atau refleksi ke garis sebagai berikut. Dengan rumus di atas akan didapatkan Hasil di atas menunjukkan bahwa matriks pencerminan terhadap garis adalah . Oleh karena itu, jawaban yang benar adalah A.

Ingat cara untuk menentukan peta atau refleksi ke garis y equals m x sebagai berikut.

$open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses equals fraction numerator 1 over denominator m squared plus 1 end fraction open parentheses table row cell 1 minus m squared end cell cell 2 m end cell row cell 2 m end cell cell m squared minus 1 end cell end table close parentheses open parentheses table row x row y end table close parentheses$

Dengan rumus di atas akan didapatkan

$table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses end cell equals cell fraction numerator 1 over denominator m squared plus 1 end fraction open parentheses table row cell 1 minus m squared end cell cell 2 m end cell row cell 2 m end cell cell m squared minus 1 end cell end table close parentheses open parentheses table row x row y end table close parentheses end cell row cell open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses end cell equals cell open parentheses table row cell fraction numerator 1 minus m squared over denominator m squared plus 1 end fraction end cell cell fraction numerator 2 m over denominator m squared plus 1 end fraction end cell row cell fraction numerator 2 m over denominator m squared plus 1 end fraction end cell cell fraction numerator m squared minus 1 over denominator m squared plus 1 end fraction end cell end table close parentheses open parentheses table row x row y end table close parentheses end cell end table$

Hasil di atas menunjukkan bahwa matriks pencerminan terhadap garis y equals m x adalah $open parentheses table row cell fraction numerator 1 minus m squared over denominator m squared plus 1 end fraction end cell cell fraction numerator 2 m over denominator m squared plus 1 end fraction end cell row cell fraction numerator 2 m over denominator m squared plus 1 end fraction end cell cell fraction numerator m squared minus 1 over denominator m squared plus 1 end fraction end cell end table close parentheses$ .

Oleh karena itu, jawaban yang benar adalah A.