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Kerjakan soal-soal berikut! Tentukan hasil pangkat tiga berikut ini.

Pertanyaan

Kerjakan soal-soal berikut!

Tentukan hasil pangkat tiga berikut ini.

begin mathsize 14px style 26 cubed equals.... end style

Pembahasan Soal:

Ingat bahwa undefined

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank rightwards arrow cell 26 cubed equals 26 cross times 26 cross times 26 end cell row blank equals cell 676 cross times 26 end cell row blank equals cell 17.576 end cell end table end style

Jadi, hasil dari begin mathsize 14px style 26 cubed end style adalah begin mathsize 14px style 17.576 end style 

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

H. Firmansyah

Mahasiswa/Alumni Universitas Gadjah Mada

Terakhir diupdate 13 September 2021

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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Pertanyaan yang serupa

Sederhanakan bentuk-bentuk di bawah ini dengan menggunakan sifat-sifat bilangan pangkat! f.

Pembahasan Soal:

Bilangan berpangkat bulat positif dapat didefinisikan sebagai berikut.

a to the power of n equals stack a cross times a cross times a cross times horizontal ellipsis cross times a with underbrace below table row blank cell space space space space space space space space end cell cell n space text faktor end text end cell end table

Ingat sifat bilangan berpangkat berikut.

a to the power of m divided by a to the power of n equals a to the power of m minus n end exponent

open parentheses a b close parentheses to the power of m equals a to the power of m times b to the power of m

open parentheses a to the power of m close parentheses to the power of n equals a to the power of m n end exponent

a to the power of 0 equals 1 comma space a not equal to 0

sehingga bentuk sederhana dari soal di atas, yaitu

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses negative 6 u cubed v close parentheses to the power of 4 divided by open parentheses 2 u v squared close parentheses squared end cell row blank equals cell open parentheses open parentheses negative 6 close parentheses to the power of 4 open parentheses u cubed close parentheses to the power of 4 open parentheses v close parentheses to the power of 4 close parentheses divided by open parentheses open parentheses 2 close parentheses squared open parentheses u close parentheses squared open parentheses v squared close parentheses squared close parentheses end cell row blank equals cell open parentheses open parentheses 2 cross times open parentheses negative 3 close parentheses close parentheses to the power of 4 times u to the power of 12 times v to the power of 4 close parentheses divided by open parentheses 2 squared times u squared times v to the power of 4 close parentheses end cell row blank equals cell open parentheses 2 to the power of 4 times open parentheses negative 3 close parentheses to the power of 4 times u to the power of 12 times v to the power of 4 close parentheses divided by open parentheses 2 squared times u squared times v to the power of 4 close parentheses end cell row blank equals cell 2 to the power of 4 minus 2 end exponent times open parentheses negative 3 close parentheses to the power of 4 times u to the power of 12 minus 2 end exponent times v to the power of 4 minus 4 end exponent end cell row blank equals cell 2 squared times 81 times u to the power of 10 times v to the power of 0 end cell row blank equals cell 2 squared times 3 to the power of 4 times u to the power of 10 times 1 end cell row blank equals cell open parentheses 2 cross times 3 squared close parentheses squared times u to the power of 10 end cell row blank equals cell 18 squared times u to the power of 10 end cell end table

Dengan demikian, bentuk sederhana dari table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses negative 6 u cubed v close parentheses to the power of 4 divided by open parentheses 2 u v squared close parentheses squared end cell equals cell 18 squared times u to the power of 10 end cell end table 

0

Roboguru

Hitunglah hasil dari bilangan berpangkat berikut. d.

Pembahasan Soal:

Bilangan berpangkat bulat positif dapat didefinisikan sebagai berikut.

a to the power of n equals stack a cross times a cross times a cross times horizontal ellipsis cross times a with underbrace below table row blank cell space space space space space space space space end cell cell n space text faktor end text end cell end table

Ingat sifat bilangan berpangkat berikut.

a to the power of negative m end exponent equals 1 over a to the power of m comma space a not equal to 0

sehingga penyelesaian soal di atas, yaitu

table attributes columnalign right center left columnspacing 0px end attributes row cell 12 to the power of negative 3 end exponent end cell equals cell 1 over 12 cubed end cell row blank equals cell fraction numerator 1 over denominator 12 cross times 12 cross times 12 end fraction end cell row blank equals cell fraction numerator 1 over denominator 1.728 end fraction end cell end table

Dengan demikian, hasil dari table attributes columnalign right center left columnspacing 0px end attributes row cell 12 to the power of negative 3 end exponent end cell equals cell fraction numerator 1 over denominator 1.728 end fraction end cell end table

0

Roboguru

Hasil pemangkatan  adalah ...

Pembahasan Soal:

Bilangan berpangkat bulat positif dapat didefinisikan sebagai berikut.

a to the power of n equals stack a cross times a cross times a cross times horizontal ellipsis cross times a with underbrace below table row blank cell space space space space space space space space end cell cell n space text faktor end text end cell end table

Ingat sifat bilangan berpangkat berikut.

a to the power of negative m end exponent equals 1 over a to the power of m comma space a not equal to 0

open parentheses a over b close parentheses to the power of m equals a to the power of m over b to the power of m comma space b not equal to 0

open parentheses a b close parentheses to the power of m equals a to the power of m times b to the power of m

open parentheses a to the power of m close parentheses to the power of n equals a to the power of m n end exponent

sehingga penyelesaian dari soal di atas, yaitu

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator 3 a squared over denominator 4 b end fraction close parentheses to the power of negative 3 end exponent end cell equals cell open parentheses 3 a squared close parentheses to the power of negative 3 end exponent over open parentheses 4 b close parentheses to the power of negative 3 end exponent end cell row blank equals cell open parentheses 4 b close parentheses cubed over open parentheses 3 a squared close parentheses cubed end cell row blank equals cell fraction numerator 4 cubed b cubed over denominator 3 cubed a to the power of 6 end fraction end cell row blank equals cell fraction numerator 64 b cubed over denominator 27 a to the power of 6 end fraction end cell end table

Oleh karena itu, jawaban yang tepat adalah D.

1

Roboguru

Hasil dari  adalah ...

Pembahasan Soal:

Bilangan berpangkat bulat positif dapat didefinisikan sebagai berikut.

a to the power of n equals stack a cross times a cross times a cross times horizontal ellipsis cross times a with underbrace below table row blank cell space space space space space space space space end cell cell n space text faktor end text end cell end table

Ingat sifat bilangan berpangkat berikut.

a to the power of negative m end exponent equals 1 over a to the power of m comma space a not equal to 0

open parentheses a over b close parentheses to the power of m equals a to the power of m over b to the power of m comma space b not equal to 0

sehingga penyelesaian soal di atas, yaitu

table attributes columnalign right center left columnspacing 0px end attributes row cell 3 to the power of negative 2 end exponent minus 6 to the power of negative 2 end exponent plus open parentheses 3 over 2 close parentheses to the power of negative 1 end exponent end cell equals cell 1 over 3 squared minus 1 over 6 squared plus 3 to the power of negative 1 end exponent over 2 to the power of negative 1 end exponent end cell row blank equals cell 1 over 9 minus 1 over 36 plus 2 over 3 end cell row blank equals cell 4 over 36 minus 1 over 36 plus 24 over 36 end cell row blank equals cell fraction numerator 4 minus 1 plus 24 over denominator 36 end fraction end cell row blank equals cell 27 over 36 end cell row blank equals cell 3 over 4 end cell end table

Dengan demikian, hasil dari table attributes columnalign right center left columnspacing 0px end attributes row cell 3 to the power of negative 2 end exponent minus 6 to the power of negative 2 end exponent plus open parentheses 3 over 2 close parentheses to the power of negative 1 end exponent end cell equals cell 3 over 4 end cell end table 

0

Roboguru

Hasil dari  adalah ...

Pembahasan Soal:

Bilangan berpangkat bulat positif dapat didefinisikan sebagai berikut.

a to the power of n equals stack a cross times a cross times a cross times horizontal ellipsis cross times a with underbrace below table row blank cell space space space space space space space space end cell cell n space text faktor end text end cell end table

Ingat sifat bilangan berpangkat berikut.

a to the power of 1 equals a

a to the power of 0 equals 1 comma space a not equal to 0

sehingga penyelesaian soal di atas, yaitu

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses negative 3 close parentheses cubed plus open parentheses negative 3 close parentheses squared plus open parentheses negative 3 close parentheses to the power of 1 plus open parentheses negative 3 close parentheses to the power of 0 end cell row blank equals cell open parentheses negative 3 close parentheses open parentheses negative 3 close parentheses open parentheses negative 3 close parentheses plus open parentheses negative 3 close parentheses open parentheses negative 3 close parentheses plus open parentheses negative 3 close parentheses plus 1 end cell row blank equals cell negative 27 plus 9 plus open parentheses negative 3 close parentheses plus 1 end cell row blank equals cell negative 20 end cell end table

Dengan demikian, hasil dari table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses negative 3 close parentheses cubed plus open parentheses negative 3 close parentheses squared plus open parentheses negative 3 close parentheses to the power of 1 plus open parentheses negative 3 close parentheses to the power of 0 end cell equals cell negative 20 end cell end table 

2

Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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