Pertanyaan

Jika x di kuadran II dan sin x = α , maka tan x adalah...

Jika x di kuadran II dan $sin x = α$ , maka $tan x$ adalah...

$negative fraction numerator alpha over denominator square root of 1 minus a squared end root end fraction$
$fraction numerator alpha over denominator square root of 1 minus a squared end root end fraction$
$fraction numerator alpha over denominator square root of 1 plus a squared end root end fraction$
$negative fraction numerator alpha over denominator square root of 1 plus a squared end root end fraction$
$negative fraction numerator 1 over denominator square root of 1 minus a squared end root end fraction$

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Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E

Pembahasan

Ingat kembali konsep dasar: teorema Pythagoras: Sehingga diperoleh perhitungan: Dengan menggunakan teorema phytagoras kita tentukan panjang sisi samping sudut: karena x berada di kuadran II maka nilai negatif, sehingga, Dengan mikian, nilai adalah Jadi, jawaban yang tepat adalah E

Ingat kembali konsep dasar:

$sin space straight x equals fraction numerator sisi space depan space sudut space over denominator sisi space miring end fraction tan space straight x equals fraction numerator sisi space depan space sudut over denominator sisi space samping space sudut end fraction$

teorema Pythagoras:

Sehingga diperoleh perhitungan:

$table row cell table attributes columnalign right center left columnspacing 0px end attributes row cell sin space x end cell equals a row cell sin space x end cell equals cell a over 1 end cell row cell fraction numerator sisi space depan space sudut over denominator sisi space miring end fraction end cell equals cell a over 1 end cell end table end cell end table space rightwards arrow table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight s end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight i end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight s end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight i end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight d end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight e end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight p end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight a end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight n end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight s end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight u end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight d end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight u end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight t end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table a rightwards arrow sisi space miring equals 1$

Dengan menggunakan teorema phytagoras kita tentukan panjang sisi samping sudut:

karena x berada di kuadran II maka nilai tan space x negatif, sehingga,

$table attributes columnalign right center left columnspacing 0px end attributes row cell tan space x end cell equals cell negative fraction numerator depan space sudut over denominator samping space sudut end fraction end cell row blank equals cell negative fraction numerator a over denominator square root of 1 minus a squared end root end fraction end cell end table$

Dengan mikian, nilai tan space x adalah $table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator a over denominator square root of 1 minus a squared end root end fraction end cell end table$

Jadi, jawaban yang tepat adalah E