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Pertanyaan

Jika f ( t ) = sin 3 4 t − ( 4 t 2 − 2 t + 4 ) ,maka nilai dari f ( 12 π ​ ) adalah ....

Jika ,  maka nilai dari  adalah .... 

  1. begin mathsize 14px style negative 18 square root of 3 minus 8 end style 

  2. begin mathsize 14px style negative 6 square root of 3 minus 8 end style 

  3. begin mathsize 14px style negative 8 end style

  4. begin mathsize 14px style 6 square root of 3 minus 8 end style 

  5. begin mathsize 14px style 18 square root of 3 minus 8 end style 

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H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

jawaban yang tepat adalah B. 

Pembahasan

Dari soal, diketahui . Untuk mencari turunan suku pertamanya, digunakan aturan rantai seperti berikut. Selanjutnya, untuk mencari turunan kedua, kita anggap dan .Maka, didapat dan . Sehingga, diperoleh Saat , didapat Jadi, jawaban yang tepat adalah B.

Dari soal, diketahui begin mathsize 14px style straight f left parenthesis straight t right parenthesis equals sin cubed invisible function application space 4 straight t minus left parenthesis 4 straight t squared minus 2 straight t plus 4 right parenthesis end style. Untuk mencari turunan suku pertamanya, digunakan aturan rantai seperti berikut.

begin mathsize 14px style straight f left parenthesis straight t right parenthesis equals sin cubed space 4 straight t space minus left parenthesis 4 straight t squared minus 2 straight t plus 4 right parenthesis straight f to the power of apostrophe left parenthesis straight t right parenthesis equals 3 times 4 open parentheses sin squared invisible function application space 4 straight t close parentheses open parentheses cos invisible function application space 4 straight t close parentheses minus left parenthesis 8 straight t minus 2 right parenthesis straight f to the power of apostrophe left parenthesis straight t right parenthesis equals 12 open parentheses sin squared invisible function application space 4 straight t close parentheses open parentheses cos invisible function application space 4 straight t close parentheses minus left parenthesis 8 straight t minus 2 right parenthesis straight f to the power of apostrophe left parenthesis straight t right parenthesis equals 6 open parentheses sin invisible function application space 4 straight t close parentheses 2 open parentheses sin invisible function application space 4 straight t close parentheses open parentheses cos invisible function application space 4 straight t close parentheses minus left parenthesis 8 straight t minus 2 right parenthesis straight f to the power of apostrophe left parenthesis straight t right parenthesis equals 6 open parentheses sin invisible function application 4 straight t close parentheses open parentheses sin invisible function application open parentheses 2 times 4 straight t close parentheses close parentheses minus left parenthesis 8 straight t minus 2 right parenthesis straight f to the power of apostrophe left parenthesis straight t right parenthesis equals 6 open parentheses sin invisible function application 4 straight t close parentheses open parentheses sin invisible function application space 8 straight t close parentheses minus left parenthesis 8 straight t minus 2 right parenthesis end style 

Selanjutnya, untuk mencari turunan kedua, kita anggap begin mathsize 14px style straight u left parenthesis straight t right parenthesis equals sin space 4 straight t end style dan begin mathsize 14px style straight v left parenthesis straight t right parenthesis equals sin space 8 straight t end style. Maka, didapat begin mathsize 14px style straight u apostrophe left parenthesis straight t right parenthesis equals 4 space cos space 4 straight t end style dan begin mathsize 14px style straight v apostrophe left parenthesis straight t right parenthesis equals 8 space cos space 8 straight t end style.

Sehingga, diperoleh

begin mathsize 14px style straight f apostrophe left parenthesis straight t right parenthesis equals 6 times straight u left parenthesis straight t right parenthesis straight v left parenthesis straight t right parenthesis minus left parenthesis 8 straight t minus 2 right parenthesis straight f apostrophe apostrophe left parenthesis straight t right parenthesis equals 6 open parentheses straight u apostrophe left parenthesis straight t right parenthesis straight v left parenthesis straight t right parenthesis plus straight v apostrophe left parenthesis straight t right parenthesis straight u left parenthesis straight t right parenthesis close parentheses minus 8 straight f apostrophe apostrophe left parenthesis straight t right parenthesis equals 6 open parentheses open parentheses 4 space cos space 4 straight t close parentheses open parentheses sin space 8 straight t close parentheses plus open parentheses 8 space cos space 8 straight t close parentheses open parentheses sin space 4 straight t close parentheses close parentheses minus 8 end style

Saat begin mathsize 14px style t equals straight pi over 12 end style, didapat

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f apostrophe apostrophe open parentheses pi over 12 close parentheses end cell equals cell 6 open parentheses 4 cos invisible function application space 4 open parentheses pi over 12 close parentheses close parentheses open parentheses sin invisible function application space 8 open parentheses pi over 12 close parentheses close parentheses plus open parentheses sin invisible function application space 4 open parentheses pi over 12 close parentheses close parentheses open parentheses 8 cos invisible function application space 8 open parentheses pi over 12 close parentheses close parentheses minus 8 end cell row blank equals cell 6 open parentheses 4 cos invisible function application space pi over 3 close parentheses open parentheses sin invisible function application space fraction numerator 2 pi over denominator 3 end fraction close parentheses plus 6 open parentheses sin invisible function application space pi over 3 close parentheses open parentheses 8 cos invisible function application space fraction numerator 2 pi over denominator 3 end fraction close parentheses minus 8 end cell row blank equals cell 6 times 2 open parentheses fraction numerator square root of 3 over denominator 2 end fraction close parentheses plus 6 open parentheses fraction numerator square root of 3 over denominator 2 end fraction close parentheses left parenthesis negative 4 right parenthesis minus 8 end cell row blank equals cell 6 square root of 3 minus 12 square root of 3 minus 8 end cell row blank equals cell negative 6 square root of 3 minus 8 end cell end table end style 

Jadi, jawaban yang tepat adalah B. 

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