Iklan

Iklan

Pertanyaan

Jika f ( t ) = sin 3 4 t − ( 4 t 2 − 2 t + 4 ) ,maka nilai dari f ( 12 π ​ ) adalah ....

Jika ,  maka nilai dari  adalah .... 

  1. begin mathsize 14px style negative 18 square root of 3 minus 8 end style 

  2. begin mathsize 14px style negative 6 square root of 3 minus 8 end style 

  3. begin mathsize 14px style negative 8 end style

  4. begin mathsize 14px style 6 square root of 3 minus 8 end style 

  5. begin mathsize 14px style 18 square root of 3 minus 8 end style 

Iklan

H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

jawaban yang tepat adalah B. 

Iklan

Pembahasan

Dari soal, diketahui . Untuk mencari turunan suku pertamanya, digunakan aturan rantai seperti berikut. Selanjutnya, untuk mencari turunan kedua, kita anggap dan .Maka, didapat dan . Sehingga, diperoleh Saat , didapat Jadi, jawaban yang tepat adalah B.

Dari soal, diketahui begin mathsize 14px style straight f left parenthesis straight t right parenthesis equals sin cubed invisible function application space 4 straight t minus left parenthesis 4 straight t squared minus 2 straight t plus 4 right parenthesis end style. Untuk mencari turunan suku pertamanya, digunakan aturan rantai seperti berikut.

begin mathsize 14px style straight f left parenthesis straight t right parenthesis equals sin cubed space 4 straight t space minus left parenthesis 4 straight t squared minus 2 straight t plus 4 right parenthesis straight f to the power of apostrophe left parenthesis straight t right parenthesis equals 3 times 4 open parentheses sin squared invisible function application space 4 straight t close parentheses open parentheses cos invisible function application space 4 straight t close parentheses minus left parenthesis 8 straight t minus 2 right parenthesis straight f to the power of apostrophe left parenthesis straight t right parenthesis equals 12 open parentheses sin squared invisible function application space 4 straight t close parentheses open parentheses cos invisible function application space 4 straight t close parentheses minus left parenthesis 8 straight t minus 2 right parenthesis straight f to the power of apostrophe left parenthesis straight t right parenthesis equals 6 open parentheses sin invisible function application space 4 straight t close parentheses 2 open parentheses sin invisible function application space 4 straight t close parentheses open parentheses cos invisible function application space 4 straight t close parentheses minus left parenthesis 8 straight t minus 2 right parenthesis straight f to the power of apostrophe left parenthesis straight t right parenthesis equals 6 open parentheses sin invisible function application 4 straight t close parentheses open parentheses sin invisible function application open parentheses 2 times 4 straight t close parentheses close parentheses minus left parenthesis 8 straight t minus 2 right parenthesis straight f to the power of apostrophe left parenthesis straight t right parenthesis equals 6 open parentheses sin invisible function application 4 straight t close parentheses open parentheses sin invisible function application space 8 straight t close parentheses minus left parenthesis 8 straight t minus 2 right parenthesis end style 

Selanjutnya, untuk mencari turunan kedua, kita anggap begin mathsize 14px style straight u left parenthesis straight t right parenthesis equals sin space 4 straight t end style dan begin mathsize 14px style straight v left parenthesis straight t right parenthesis equals sin space 8 straight t end style. Maka, didapat begin mathsize 14px style straight u apostrophe left parenthesis straight t right parenthesis equals 4 space cos space 4 straight t end style dan begin mathsize 14px style straight v apostrophe left parenthesis straight t right parenthesis equals 8 space cos space 8 straight t end style.

Sehingga, diperoleh

begin mathsize 14px style straight f apostrophe left parenthesis straight t right parenthesis equals 6 times straight u left parenthesis straight t right parenthesis straight v left parenthesis straight t right parenthesis minus left parenthesis 8 straight t minus 2 right parenthesis straight f apostrophe apostrophe left parenthesis straight t right parenthesis equals 6 open parentheses straight u apostrophe left parenthesis straight t right parenthesis straight v left parenthesis straight t right parenthesis plus straight v apostrophe left parenthesis straight t right parenthesis straight u left parenthesis straight t right parenthesis close parentheses minus 8 straight f apostrophe apostrophe left parenthesis straight t right parenthesis equals 6 open parentheses open parentheses 4 space cos space 4 straight t close parentheses open parentheses sin space 8 straight t close parentheses plus open parentheses 8 space cos space 8 straight t close parentheses open parentheses sin space 4 straight t close parentheses close parentheses minus 8 end style

Saat begin mathsize 14px style t equals straight pi over 12 end style, didapat

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f apostrophe apostrophe open parentheses pi over 12 close parentheses end cell equals cell 6 open parentheses 4 cos invisible function application space 4 open parentheses pi over 12 close parentheses close parentheses open parentheses sin invisible function application space 8 open parentheses pi over 12 close parentheses close parentheses plus open parentheses sin invisible function application space 4 open parentheses pi over 12 close parentheses close parentheses open parentheses 8 cos invisible function application space 8 open parentheses pi over 12 close parentheses close parentheses minus 8 end cell row blank equals cell 6 open parentheses 4 cos invisible function application space pi over 3 close parentheses open parentheses sin invisible function application space fraction numerator 2 pi over denominator 3 end fraction close parentheses plus 6 open parentheses sin invisible function application space pi over 3 close parentheses open parentheses 8 cos invisible function application space fraction numerator 2 pi over denominator 3 end fraction close parentheses minus 8 end cell row blank equals cell 6 times 2 open parentheses fraction numerator square root of 3 over denominator 2 end fraction close parentheses plus 6 open parentheses fraction numerator square root of 3 over denominator 2 end fraction close parentheses left parenthesis negative 4 right parenthesis minus 8 end cell row blank equals cell 6 square root of 3 minus 12 square root of 3 minus 8 end cell row blank equals cell negative 6 square root of 3 minus 8 end cell end table end style 

Jadi, jawaban yang tepat adalah B. 

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Iklan

Pertanyaan serupa

Jika f ( t ) = cos 2 ( 2 t + 2 π ​ ) ,maka f ( 6 π ​ ) = ....

1

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia