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Jika begin mathsize 14px style straight A equals open parentheses table row 2 cell negative 4 end cell row 3 5 end table close parentheses space dan space straight B equals open parentheses table row cell negative 1 end cell 2 row 1 cell negative 6 end cell end table close parentheses end style maka hasil dari AB-BA=...

  1. open parentheses table row cell size 14px minus size 14px 10 end cell size 14px 14 row size 14px 18 size 14px 10 end table close parentheses

  2. open parentheses table row size 14px 10 size 14px 14 row cell size 14px minus size 14px 18 end cell size 14px 10 end table close parentheses

  3. open parentheses table row size 14px 10 cell size 14px minus size 14px 14 end cell row cell size 14px minus size 14px 18 end cell cell size 14px minus size 14px 10 end cell end table close parentheses

  4. open parentheses table row size 14px 10 cell size 14px minus size 14px 14 end cell row size 14px 18 size 14px 10 end table close parentheses

  5. open parentheses table row size 14px 0 0 row 0 size 14px 0 end table close parentheses

N. Mustikowati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style straight A equals open parentheses table row 2 cell negative 4 end cell row 3 5 end table close parentheses space dan space straight B equals open parentheses table row cell negative 1 end cell 2 row 1 cell negative 6 end cell end table close parentheses  asterisk times space A B space equals space open parentheses table row 2 cell negative 4 end cell row 3 5 end table close parentheses open parentheses table row cell negative 1 end cell 2 row 1 cell negative 6 end cell end table close parentheses  space space space space space space space space equals open parentheses table row cell negative 2 minus 4 end cell cell space space 4 plus 24 end cell row cell negative 3 plus 5 end cell cell space 6 minus 30 end cell end table close parentheses  space space space space space space space space equals open parentheses table row cell negative 6 end cell 28 row 2 cell negative 24 end cell end table close parentheses  asterisk times B A space equals open parentheses table row cell negative 1 end cell 2 row 1 cell negative 6 end cell end table close parentheses space open parentheses table row 2 cell negative 4 end cell row 3 5 end table close parentheses  space space space space space space space space equals open parentheses table row cell negative 2 plus 6 end cell cell space space 4 plus 10 end cell row cell 2 minus 18 end cell cell space minus 4 minus 30 end cell end table close parentheses  space space space space space space space space equals open parentheses table row 4 14 row cell negative 16 end cell cell negative 34 end cell end table close parentheses  asterisk times A B minus B A space equals open parentheses table row cell negative 6 end cell 28 row 2 cell negative 24 end cell end table close parentheses minus open parentheses table row 4 14 row cell negative 16 end cell cell negative 34 end cell end table close parentheses  space space space space space space space space space space space space space space space equals open parentheses table row cell negative 6 minus 4 end cell cell 28 minus 14 end cell row cell 2 plus 16 end cell cell negative 24 plus 34 end cell end table close parentheses  space space space space space space space space space space space space space space space equals open parentheses table row cell negative 10 end cell 14 row 18 10 end table close parentheses end style

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Hitunglah nilai dari masing-masing huruf pada persamaan matriks berikut. 2(10​43​)+(1−1​23​)(25​4−4​)=(ac​bd​)

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