Pertanyaan

Jika , maka ...

Jika $begin mathsize 14px style limit as x rightwards arrow 1 of invisible function application fraction numerator f open parentheses x close parentheses over denominator f open parentheses x close parentheses plus g open parentheses x close parentheses end fraction equals 6 end style$ , maka $begin mathsize 14px style limit as x rightwards arrow 1 of invisible function application fraction numerator f open parentheses x close parentheses over denominator g open parentheses x close parentheses end fraction equals end style$ ...

S. Nur

Master Teacher

Jawaban terverifikasi

Pembahasan

Maka, jawaban yang tepat adalah D.

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 1 of invisible function application fraction numerator f open parentheses x close parentheses over denominator f open parentheses x close parentheses plus g open parentheses x close parentheses end fraction end cell equals 6 row cell fraction numerator limit as x rightwards arrow 1 of invisible function application f open parentheses x close parentheses over denominator limit as x rightwards arrow 1 of invisible function application f open parentheses x close parentheses plus limit as x rightwards arrow 1 of invisible function application g open parentheses x close parentheses end fraction end cell equals 6 row cell limit as x rightwards arrow 1 of invisible function application f open parentheses x close parentheses end cell equals cell 6 open parentheses limit as x rightwards arrow 1 of invisible function application f open parentheses x close parentheses plus limit as x rightwards arrow 1 of invisible function application g open parentheses x close parentheses close parentheses end cell row cell limit as x rightwards arrow 1 of invisible function application f open parentheses x close parentheses end cell equals cell 6 limit as x rightwards arrow 1 of invisible function application f open parentheses x close parentheses plus 6 limit as x rightwards arrow 1 of invisible function application g open parentheses x close parentheses end cell row cell negative 5 limit as x rightwards arrow 1 of invisible function application f open parentheses x close parentheses end cell equals cell 6 limit as x rightwards arrow 1 of invisible function application g open parentheses x close parentheses end cell row cell fraction numerator limit as x rightwards arrow 1 of invisible function application f open parentheses x close parentheses over denominator limit as x rightwards arrow 1 of invisible function application g open parentheses x close parentheses end fraction end cell equals cell negative 6 over 5 end cell row cell limit as x rightwards arrow 1 of invisible function application fraction numerator f open parentheses x close parentheses over denominator g open parentheses x close parentheses end fraction end cell equals cell negative 6 over 5 end cell end table end style$

Maka, jawaban yang tepat adalah D.