Iklan

Pertanyaan

l i m x → 3 ​ x − 3 3 x 12 ​ ​ − 9 ​ = ....

  1. 0

  2. 3

  3. 6

  4. 8

  5. infinity

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

00

:

02

:

37

:

12

Klaim

Iklan

R. RGFLSATU

Master Teacher

Jawaban terverifikasi

Pembahasan

table attributes columnalign right center left columnspacing 0px end attributes row cell L i m subscript x rightwards arrow 3 end subscript fraction numerator cube root of root index blank of x to the power of 12 end root end root plus 3 over denominator x minus 3 end fraction end cell equals cell fraction numerator open parentheses open parentheses x to the power of 12 close parentheses to the power of 1 half end exponent close parentheses to the power of bevelled 1 third end exponent minus 9 over denominator x minus 3 end fraction end cell row blank equals cell fraction numerator x cubed minus 9 over denominator x minus 3 end fraction equals fraction numerator left parenthesis x minus 3 right parenthesis left parenthesis x plus 3 right parenthesis over denominator left parenthesis x minus 3 right parenthesis end fraction end cell row cell space space end cell equals cell x plus 3 end cell row blank equals cell 3 plus 3 end cell row blank equals 6 end table

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Pertanyaan serupa

L i m x → 1 ​ x − 1 x 2 − 1 ​ = ....

23

3.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2025 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia