Roboguru

Jika koordinat titik , dan , nilai  adalah ...

Pertanyaan

Jika koordinat titik straight A left parenthesis straight m comma negative 5 comma space 2 straight n right parenthesis comma space straight B left parenthesis straight n comma space 2 straight m comma space straight m plus 2 right parenthesis, dan AB with rightwards arrow on top equals open parentheses table row cell negative 7 end cell row cell 1 minus 4 straight n end cell row cell 3 straight m end cell end table close parentheses, nilai straight m adalah ...

  1. 4  

  2. 3  

  3. 1  

  4. negative 3  

  5. negative 4  

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell stack A B with rightwards arrow on top end cell equals cell open parentheses table row cell negative 7 end cell row cell 1 minus 4 n end cell row cell 3 m end cell end table close parentheses end cell row cell B minus A end cell equals cell open parentheses table row cell negative 7 end cell row cell 1 minus 4 n end cell row cell 3 m end cell end table close parentheses end cell row cell open parentheses table row n row cell 2 m end cell row cell m plus 2 end cell end table close parentheses minus open parentheses table row m row cell negative 5 end cell row cell 2 n end cell end table close parentheses end cell equals cell open parentheses table row cell negative 7 end cell row cell 1 minus 4 n end cell row cell 3 m end cell end table close parentheses end cell row cell open parentheses table row cell n minus m end cell row cell 2 m plus 5 end cell row cell m plus 2 n plus 2 end cell end table close parentheses end cell equals cell open parentheses table row cell negative 7 end cell row cell 1 minus 4 n end cell row cell 3 m end cell end table close parentheses end cell end table 

Dari kesamaan tersebut diperoleh 

table attributes columnalign right center left columnspacing 0px end attributes row cell n minus m end cell equals cell negative 7 space end cell row n equals cell m minus 7 space... space open parentheses 1 close parentheses end cell row blank blank blank row cell 2 m plus 5 end cell equals cell 1 minus 4 n end cell row cell 2 m plus 4 n end cell equals cell negative 4 space... space open parentheses 2 close parentheses end cell row blank blank blank row cell m minus 2 n plus 2 end cell equals cell 3 m space end cell row cell negative 2 m minus 2 n end cell equals cell negative 2 space... space open parentheses 3 close parentheses end cell end table    

Substitusi persamaan open parentheses 1 close parentheses ke persamaan open parentheses 2 close parentheses, diperoleh 

table attributes columnalign right center left columnspacing 0px end attributes row cell 2 m plus 4 n end cell equals cell negative 4 end cell row cell 2 m plus 4 open parentheses m minus 7 close parentheses end cell equals cell negative 4 end cell row cell 2 m plus 4 m minus 28 end cell equals cell negative 4 end cell row cell 6 m minus 28 end cell equals cell negative 4 end cell row cell 6 m end cell equals 24 row m equals 4 end table     

Dengan demikian, jawaban yang tepat adalah A.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 Juni 2021

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