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Jika kelarutan AgCN = 2 × 1 0 − 4 M , tentukan K sp ​ !

Jika kelarutan , tentukan !space 

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S. Lubis

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Jadi adalah .

Ag C N open parentheses italic s close parentheses equilibrium Ag to the power of plus sign left parenthesis italic a italic q right parenthesis plus C N to the power of minus sign left parenthesis italic a italic q right parenthesis space space space space space italic s italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic s italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic s  K subscript sp space Ag C N equals open square brackets Ag to the power of plus sign close square brackets open square brackets C N to the power of minus sign close square brackets K subscript sp space Ag C N equals open square brackets italic s close square brackets open square brackets italic s close square brackets K subscript sp space Ag C N equals italic s squared K subscript italic sp space Ag C N equals left parenthesis 2 cross times 10 to the power of negative sign 4 end exponent space M right parenthesis squared space K subscript italic s italic p end subscript space Ag C N equals 4 cross times 10 to the power of negative sign 8 end exponent 

Jadi K subscript bold sp bold space end subscript Ag C N adalah bold 4 bold cross times bold 10 to the power of bold minus sign bold 8 end exponent.space 

 

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