Pertanyaan

Diketahui hasil kali kelarutan, K sp Ca ( OH ) 2 = 8.1 0 − 6 . Tentukan kelarutan Ca ( OH ) 2 , dalam air!

Diketahui hasil kali kelarutan, $K_{sp} Ca (OH)_{2} = 8.1 0^{- 6}$ . Tentukan kelarutan $Ca (OH)_{2}$ , dalam air!

R. Anisa

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

kelarutan dalam air yaitu .

kelarutan

begin mathsize 14px style Ca open parentheses O H close parentheses subscript 2 end style

dalam air yaitu 1 comma 26.10 to the power of negative sign 2 end exponent space M

Pembahasan

Kelarutan : Jadi, kelarutan dalam air yaitu .

Kelarutan begin mathsize 14px style Ca open parentheses O H close parentheses subscript 2 end style :

Ca open parentheses O H close parentheses subscript 2 equilibrium Ca to the power of 2 plus sign and 2 O H to the power of minus sign space space space s space space space space space space space space space space space space space space s space space space space space space space space space space 2 s

$space space space space space space K subscript sp double bond open square brackets Ca to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared space 8.10 to the power of negative sign 6 end exponent equals s point left parenthesis 2 s right parenthesis squared space 8.10 to the power of negative sign 6 end exponent equals 4 s cubed space space space space space space space s cubed equals fraction numerator 8.10 to the power of negative sign 6 end exponent over denominator 4 end fraction space space space space space space space space space space equals 2.10 to the power of negative sign 6 end exponent space space space space space space space space s equals cube root of 2.10 to the power of negative sign 6 end exponent end root space space space space space space space space space space equals 1 comma 26.10 to the power of negative sign 2 end exponent$

Jadi, kelarutan dalam air yaitu .