Pertanyaan

Jika f ( x ) = 4 ( 2 x − 3 ) , x > 2 3 maka nilai dari 4 ⋅ f ( 2 x − 3 ) adalah ….

Jika $f (x) = 4 (2 x - 3)$ , $x > \frac{3}{2}$ maka nilai dari $4 \cdot f (2 x - 3)$ adalah ….

$begin mathsize 14px style fraction numerator 1 over denominator 4 fourth root of open parentheses 2 straight x minus 3 close parentheses end root end fraction end style$
$begin mathsize 14px style fraction numerator 4 over denominator fourth root of open parentheses 2 x minus 3 close parentheses cubed end root end fraction end style$
$begin mathsize 14px style fraction numerator 4 over denominator fourth root of open parentheses 4 straight x minus 9 close parentheses cubed end root end fraction end style$
$begin mathsize 14px style fraction numerator 1 over denominator 4 fourth root of open parentheses 4 x minus 9 close parentheses cubed end root end fraction end style$
$begin mathsize 14px style fraction numerator 1 over denominator fourth root of open parentheses 4 x minus 9 close parentheses cubed end root end fraction end style$

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Jawaban terverifikasi

Jawaban

jawaban yang benar adalah C.

Pembahasan

Sehingga, Misalkan: Kemudian, hitung turunan pertama . Maka diperoleh Jadi, jawaban yang benar adalah C.

Sehingga,

Misalkan:

Kemudian, hitung turunan pertama .

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight f left parenthesis 2 straight x minus 3 right parenthesis end cell equals cell straight u to the power of 1 fourth end exponent end cell row cell straight f to the power of apostrophe left parenthesis 2 straight x minus 3 right parenthesis end cell equals cell 1 fourth straight u to the power of 1 fourth minus 1 end exponent times straight u to the power of apostrophe end cell row blank equals cell 1 fourth straight u to the power of 3 over 4 end exponent times 4 end cell row blank equals cell 1 over straight u to the power of begin display style 3 over 4 end style end exponent end cell row blank equals cell fraction numerator 1 over denominator fourth root of left parenthesis 4 straight x minus 9 right parenthesis cubed end root end fraction end cell end table end style$

Maka diperoleh

$begin mathsize 14px style 4 times straight f to the power of apostrophe left parenthesis 2 straight x minus 3 right parenthesis equals fraction numerator 4 over denominator fourth root of left parenthesis 4 straight x minus 9 right parenthesis cubed end root end fraction end style$

Jadi, jawaban yang benar adalah C.