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Pertanyaan

Jika diketahui fungsi f ( x ) = 3 x − 2 , g ( x ) = 2 x + 1 ​ , maka ( f − 1 ∘ g − 1 ∘ h − 1 ) ( x ) =....

Jika diketahui fungsi =....

  1. fraction numerator x minus 60 over denominator 13 end fraction

  2. fraction numerator x plus 30 over denominator 13 end fraction

  3. fraction numerator x minus 30 over denominator 13 end fraction

  4. fraction numerator x plus 13 over denominator 30 end fraction

  5. fraction numerator x minus 13 over denominator 30 end fraction

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S. Nur

Master Teacher

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Pembahasan

Penyelesaian:

Penyelesaian:

  • f left parenthesis x right parenthesis equals 3 x minus 2  y equals 3 x minus 2  3 x equals y plus 2 left right double arrow x equals fraction numerator y plus 2 over denominator 3 end fraction  f to the power of negative 1 end exponent left parenthesis x right parenthesis equals fraction numerator x plus 2 over denominator 3 end fraction
  • g left parenthesis x right parenthesis equals square root of 2 x plus 1 end root  y equals square root of 2 x plus 1 end root  y squared equals 2 x plus 1  2 x equals y squared minus 1  x equals fraction numerator y squared minus 1 over denominator 2 end fraction  g to the power of negative 1 end exponent left parenthesis x right parenthesis equals fraction numerator x squared minus 1 over denominator 2 end fraction
  • h left parenthesis x right parenthesis equals 5 x squared plus 2  y equals 5 x squared plus 2  y minus 2 equals 5 x squared  x squared equals fraction numerator y minus 2 over denominator 5 end fraction  x equals square root of fraction numerator y minus 2 over denominator 5 end fraction end root  h to the power of negative 1 end exponent left parenthesis x right parenthesis equals square root of fraction numerator x minus 2 over denominator 5 end fraction end root
  • M i s a l space left parenthesis g to the power of negative 1 end exponent ring operator h to the power of negative 1 end exponent right parenthesis left parenthesis x right parenthesis equals p left parenthesis x right parenthesis  left parenthesis g to the power of negative 1 end exponent ring operator h to the power of negative 1 end exponent right parenthesis left parenthesis x right parenthesis equals left parenthesis g to the power of negative 1 end exponent left parenthesis h to the power of negative 1 end exponent left parenthesis x right parenthesis right parenthesis right parenthesis  equals g to the power of negative 1 end exponent open parentheses square root of fraction numerator x minus 2 over denominator 5 end fraction end root close parentheses squared minus 1  equals fraction numerator begin display style fraction numerator x minus 2 over denominator 5 end fraction end style minus begin display style 5 over 5 end style over denominator 2 end fraction equals fraction numerator x minus 7 over denominator 5 end fraction.1 half  equals fraction numerator x minus 7 over denominator 10 end fraction    p left parenthesis x right parenthesis equals fraction numerator x minus 7 over denominator 10 end fraction  left parenthesis f to the power of negative 1 end exponent ring operator g to the power of negative 1 end exponent ring operator h to the power of negative 1 end exponent right parenthesis left parenthesis x right parenthesis equals left parenthesis f to the power of negative 1 end exponent ring operator p right parenthesis left parenthesis x right parenthesis  left parenthesis f to the power of negative 1 end exponent left parenthesis p right parenthesis right parenthesis left parenthesis x right parenthesis equals f to the power of negative 1 end exponent open parentheses fraction numerator x minus 7 over denominator 10 end fraction close parentheses  equals fraction numerator begin display style fraction numerator x minus 7 over denominator 10 end fraction end style plus 2 over denominator 3 end fraction  equals fraction numerator x plus 13 over denominator 10 end fraction.1 third equals fraction numerator x plus 13 over denominator 30 end fraction

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Jika diketahui fungsi f ( x ) = 2 x − 7 , g ( x ) = x 2 + 5 , d an ( x ) 2 x 2 − 1. M aka ( f ∘ g ∘ h − 1 ) ( x ) =...

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