Pertanyaan

Jika x  = 0 dan y  = 0 maka [ ( x . y a ) 1 − a ] 2 . [ ( x . y a ) a − 1 ] 2 = ...

Jika $x \neq = 0$ dan $y \neq = 0$ maka $[(x . y^{a})^{1 - a}]^{2} . [(x . y^{a})^{a - 1}]^{2} = ...$

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

Pembahasan

Ingat! Sifat bilangan berpangkat: Maka: [ ( x . y a ) 1 − a ] 2 . [ ( x . y a ) a − 1 ] 2 = = = = = = = = = [ x 1 − a . ( y a ) 1 − a ] 2 . [ ( x a − 1 . ( y a ) a − 1 ) ] 2 [ x 1 − a ⋅ y a × ( 1 − a ) ] 2 [ ( x a − 1 ⋅ y a × ( a − 1 ) ) ] 2 [ x 1 − a ⋅ y a − a 2 ] 2 ⋅ [ x a − 1 ⋅ y a 2 − a ] 2 x ( 1 − a ) × 2 ⋅ y ( a − a 2 ) × 2 ⋅ x ( a − 1 ) × 2 ⋅ y ( a 2 − a ) × 2 x 2 − 2 a ⋅ y 2 a − 2 a 2 ⋅ x 2 a − 2 ⋅ y 2 a 2 − 2 a x 2 − 2 a + 2 a − 2 ⋅ y 2 a − 2 a 2 + 2 a 2 − 2 a x 0 ⋅ y 0 ( 1 ) ⋅ ( 1 ) 1 Jadi, jawaban yang tepat adalah E.

Ingat!

Sifat bilangan berpangkat:

Maka:

$[(x . y^{a})^{1 - a}]^{2} . [(x . y^{a})^{a - 1}]^{2} = = = = = = = = = [x^{1 - a} . (y^{a})^{1 - a}]^{2} . [(x^{a - 1} . (y^{a})^{a - 1})]^{2} [x^{1 - a} \cdot y^{a \times (1 - a)}]^{2} [(x^{a - 1} \cdot y^{a \times (a - 1)})]^{2} [x^{1 - a} \cdot y^{a - a^{2}}]^{2} \cdot [x^{a - 1} \cdot y^{a^{2} - a}]^{2} x^{(1 - a) \times 2} \cdot y^{(a - a^{2}) \times 2} \cdot x^{(a - 1) \times 2} \cdot y^{(a^{2} - a) \times 2} x^{2 - 2 a} \cdot y^{2 a - 2 a^{2}} \cdot x^{2 a - 2} \cdot y^{2 a^{2} - 2 a} x^{2 - 2 a + 2 a - 2} \cdot y^{2 a - 2 a^{2} + 2 a^{2} - 2 a} x^{0} \cdot y^{0} (1) \cdot (1) 1$