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Jika f ( x ) = x 2 , g ( x ) = 2 x + 1 , dan h ( x ) = x 1 ​ , maka ( h ∘ g ∘ f ) ( x ) = ....

Jika , dan , maka ....

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Y. Umi

Master Teacher

Mahasiswa/Alumni Universitas Gadjah Mada

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 begin mathsize 14px style open parentheses h ring operator g ring operator f close parentheses open parentheses x close parentheses equals fraction numerator 1 over denominator 2 x squared plus 1 end fraction end style.

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Pembahasan

, , dan . Diperoleh Jadi, .

 begin mathsize 14px style f open parentheses x close parentheses equals x squared end stylebegin mathsize 14px style g open parentheses x close parentheses equals 2 x plus 1 end style, dan begin mathsize 14px style h open parentheses x close parentheses equals 1 over x end style. Diperoleh

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses h ring operator g ring operator f close parentheses open parentheses x close parentheses end cell equals cell h open parentheses g open parentheses f open parentheses x close parentheses close parentheses close parentheses end cell row blank equals cell h open parentheses g open parentheses x squared close parentheses close parentheses end cell row blank equals cell h open parentheses 2 x squared plus 1 close parentheses end cell row blank equals cell fraction numerator 1 over denominator 2 x squared plus 1 end fraction end cell end table end style

Jadi, begin mathsize 14px style open parentheses h ring operator g ring operator f close parentheses open parentheses x close parentheses equals fraction numerator 1 over denominator 2 x squared plus 1 end fraction end style.

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Jika diketahui f ( x ) = 4 x 2 + 3 , g ( x ) = x − 5 dan h ( x ) = 2 x ​ . Rumus komposisi fungsi ( f ∘ g ∘ h ) ( x ) adalah ...

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