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Pertanyaan

Jika a ⇀ = ⎣ ⎡ ​ 2 − 1 0 ​ ⎦ ⎤ ​ dan b ⇀ = ⎣ ⎡ ​ − 1 2 1 ​ ⎦ ⎤ ​ maka 2 a ⇀ + 3 b ⇀ = ...

Jika  dan  maka  = ...

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N. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Padang

Jawaban terverifikasi

Jawaban

hasil dari adalah .

hasil dari 2 straight a with rightwards harpoon with barb upwards on top plus 3 straight b with rightwards harpoon with barb upwards on top adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open square brackets table row 1 row 4 row 3 end table close square brackets end cell end table.

Pembahasan

Perhatikan perhitungan berikut. Jadi, hasil dari adalah .

Perhatikan perhitungan berikut.

table attributes columnalign right center left columnspacing 0px end attributes row cell 2 straight a with rightwards harpoon with barb upwards on top plus 3 straight b with rightwards harpoon with barb upwards on top end cell equals cell 2 open square brackets table row 2 row cell negative 1 end cell row 0 end table close square brackets plus 3 open square brackets table row cell negative 1 end cell row 2 row 1 end table close square brackets end cell row blank equals cell open square brackets table row 4 row cell negative 2 end cell row 0 end table close square brackets plus open square brackets table row cell negative 3 end cell row 6 row 3 end table close square brackets end cell row blank equals cell open square brackets table attributes rowalign center baseline baseline end attributes row cell 4 minus 3 end cell row cell negative 2 plus 6 end cell row cell 0 plus 3 end cell end table close square brackets end cell row blank equals cell open square brackets table row 1 row 4 row 3 end table close square brackets end cell end table

Jadi, hasil dari 2 straight a with rightwards harpoon with barb upwards on top plus 3 straight b with rightwards harpoon with barb upwards on top adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open square brackets table row 1 row 4 row 3 end table close square brackets end cell end table.

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Diketahui vektor p ​ = ( 3 4 ​ ) , vektor q ​ = ( 5 − 1 ​ ) , dan vektor r = ( − 2 6 ​ ) . Tentukan: b) p ​ + 2 q ​ − 3 r

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