Pertanyaan

Hasil dari adalah ....

Hasil dari $begin mathsize 14px style open parentheses fraction numerator 27 m cubed over denominator 8 end fraction close parentheses to the power of 1 1 third end exponent end style$ adalah ....

$begin mathsize 14px style fraction numerator 81 m to the power of 4 over denominator 16 end fraction end style$
$begin mathsize 14px style fraction numerator 3 m to the power of 4 over denominator 2 end fraction end style$
$begin mathsize 14px style fraction numerator 81 m over denominator 16 end fraction end style$
$begin mathsize 14px style fraction numerator 3 m over denominator 2 end fraction end style$

S. Rahmi

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah A.

Pembahasan

Perhatikan perhitungan berikut! Jadi, jawaban yang tepat adalah A.

Perhatikan perhitungan berikut!

$begin mathsize 14px style open parentheses fraction numerator 27 m cubed over denominator 8 end fraction close parentheses to the power of 1 1 third end exponent equals open parentheses fraction numerator 27 m cubed over denominator 8 end fraction close parentheses to the power of 4 over 3 end exponent space space space space space space space space space space space space space space space space space space equals open parentheses 27 m cubed close parentheses to the power of 4 over 3 end exponent over open parentheses 8 close parentheses to the power of 4 over 3 end exponent space space space space space space space space space space space space space space space space space space equals open parentheses 3 cubed m cubed close parentheses to the power of 4 over 3 end exponent over open parentheses 2 cubed close parentheses to the power of 4 over 3 end exponent space space space space space space space space space space space space space space space space space space equals fraction numerator open parentheses 3 cubed close parentheses to the power of 4 over 3 end exponent open parentheses m cubed close parentheses to the power of 4 over 3 end exponent over denominator open parentheses 2 cubed close parentheses to the power of 4 over 3 end exponent end fraction space space space space space space space space space space space space space space space space space space equals fraction numerator 3 to the power of 3 open parentheses 4 over 3 close parentheses end exponent m to the power of 3 open parentheses 4 over 3 close parentheses end exponent over denominator 2 to the power of 3 open parentheses 4 over 3 close parentheses end exponent end fraction space space space space space space space space space space space space space space space space space space equals fraction numerator 3 to the power of 4 m to the power of 4 over denominator 2 to the power of 4 end fraction space space space space space space space space space space space space space space space space space space equals box enclose fraction numerator 81 m to the power of 4 over denominator 16 end fraction end enclose end style$

Jadi, jawaban yang tepat adalah A.