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Pertanyaan

Jika a + b + c = 0, maka nilai dari b 2 + c 2 − a 2 1 ​ + c 2 + a 2 − b 2 1 ​ + a 2 + b 2 − c 2 1 ​ = ...

Jika a + b + c = 0, maka nilai dari 

  1. 0

  2. fraction numerator 1 over denominator a plus b end fraction

  3. fraction numerator 1 over denominator a minus b end fraction

  4. fraction numerator a plus b over denominator a minus b end fraction

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N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

Diketahui a + b + c = 0 maka c = - (a + b) sehingga:

Diketahui a + b + c = 0

maka c = - (a + b)

sehingga:

fraction numerator 1 over denominator b squared plus c squared minus a squared end fraction plus fraction numerator 1 over denominator c squared plus a squared minus b squared end fraction plus fraction numerator 1 over denominator a squared plus b squared minus c squared end fraction  equals fraction numerator 1 over denominator b squared plus open parentheses negative open parentheses a plus b close parentheses close parentheses squared minus a squared end fraction plus fraction numerator 1 over denominator open parentheses negative open parentheses a plus b close parentheses close parentheses squared plus a squared minus b squared end fraction plus fraction numerator 1 over denominator a squared plus b squared minus open parentheses negative open parentheses a plus b close parentheses close parentheses squared end fraction  equals fraction numerator 1 over denominator b squared plus a squared plus 2 a b plus b squared minus a squared end fraction plus fraction numerator 1 over denominator a squared plus 2 a b plus b squared plus a squared minus b squared end fraction plus fraction numerator 1 over denominator a squared plus b squared minus open parentheses a squared plus 2 a b plus b squared close parentheses end fraction  equals fraction numerator 1 over denominator 2 b squared plus 2 a b end fraction plus fraction numerator 1 over denominator 2 a squared plus 2 a b end fraction plus fraction numerator 1 over denominator negative 2 a b end fraction  equals fraction numerator 1 over denominator 2 b open parentheses b plus a close parentheses end fraction plus fraction numerator 1 over denominator 2 a left parenthesis a plus b right parenthesis end fraction minus fraction numerator 1 over denominator 2 a b end fraction  equals fraction numerator 1 over denominator 2 open parentheses a plus b close parentheses end fraction open parentheses 1 over b plus 1 over a close parentheses minus fraction numerator 1 over denominator 2 a b end fraction  equals fraction numerator 1 over denominator 2 open parentheses a plus b close parentheses end fraction open parentheses fraction numerator a plus b over denominator a b end fraction close parentheses minus fraction numerator 1 over denominator 2 a b end fraction  equals fraction numerator 1 over denominator 2 a b end fraction minus fraction numerator 1 over denominator 2 a b end fraction  equals 0

 

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Dengan terlebih dahulu menyamakan penyebut, sederhanakanpecahan-pecahan berikut! 2 x − 3 ​ + 9 5 x ​ − 6 x + 1 ​

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