Pertanyaan

Jika 50 mL CH 3 COOH 0,1 M direaksikan dengan 50 mL NaOH 0,1 M menghasilkan garam sesuai reaksi CH 3 COOH(aq) + NaOH(aq) → CH 3 COOH(aq) + H 2 O(l). pH larutan yang terjadi jika diketahui Ka CH 3 COOH = 10 -5 adalah ...

Jika 50 mL CH₃COOH 0,1 M direaksikan dengan 50 mL NaOH 0,1 M menghasilkan garam sesuai reaksi CH₃COOH(aq) + NaOH(aq) $\to$ CH₃COOH(aq) + H₂O(l). pH larutan yang terjadi jika diketahui Ka CH₃COOH = 10^-5 adalah ...

6 - log 7,1
6 + log 7,1
8 + log 7,1
8 - log 7,1
9 - log 7,1

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Pembahasan

$begin mathsize 14px style Mol space CH subscript 3 COOH space equals space straight M space cross times space straight V space equals space 0 comma 1 space straight M space cross times space 50 space mL space equals space 50 space mmol Mol space NaOH space equals space straight M space cross times space straight V space equals space 0 comma 1 space straight M space cross times space 50 space mL space equals space 5 space mmol Persamaan space reaksi colon space space space space space space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold CH subscript bold 3 bold COOH bold left parenthesis bold aq bold right parenthesis bold space bold plus bold space bold NaOH bold left parenthesis bold aq bold right parenthesis bold space bold rightwards arrow bold space bold CH subscript bold 3 bold COONa bold left parenthesis bold aq bold right parenthesis bold space bold plus bold space bold H subscript bold 2 bold O bold left parenthesis bold l bold right parenthesis Mula minus mula space colon space space space space space space space space 5 space mmol space space space space space space space space space space space space 5 space mmol space space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space minus Reaksi space space space space space space space space space colon space space space space minus 5 space mmol space space space space space space space space space minus 5 space mmol space space space space space space space space space space space space space space plus space 5 space mmol space space space space space space space plus space 5 mmol stack Sisa space space space space space space space space space space space space space colon space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space space 5 space mmol space space space space space space space space space space space space 5 space mmol with bar on top Karena space yang space tersisa space hanya space garam space dan space air comma space maka space menggunakan space rumus space hidrolisis. space left square bracket straight G right square bracket space equals fraction numerator m m o l over denominator m L space v o l u m e end fraction space equals space fraction numerator 5 space m m o l over denominator 100 space m L end fraction equals space 5.10 to the power of negative 2 end exponent space straight M OH space equals square root of fraction numerator K w over denominator K a end fraction left square bracket G right square bracket end root space equals square root of 10 to the power of negative 14 end exponent over 10 to the power of negative 5 end exponent x space 5 space. space 10 to the power of negative 2 end exponent end root space equals 7 comma 1 space straight x space 10 to the power of negative 6 end exponent pOH equals space minus space log space left square bracket OH minus right square bracket space space space space space space space equals space minus log space cross times space 7 comma 1 space 10 to the power of negative 6 end exponent space equals space 6 space minus space log space 7 comma 1 pH equals space 14 minus space left parenthesis 6 minus space log space 7 comma 1 right parenthesis equals 8 space plus space log space 7 comma 1 end style$

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