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Pertanyaan

Jika 50 mL CH3COOH 0,1 M direaksikan dengan 50 mL NaOH 0,1 M menghasilkan garam sesuai reaksi CH3COOH(aq) + NaOH(aq) rightwards arrow CH3COOH(aq) + H2O(l). pH larutan yang terjadi jika diketahui Ka CH3COOH = 10-5 adalah ...

  1. 6 - log 7,1

  2. 6 + log 7,1

  3. 8 + log 7,1

  4. 8 - log 7,1

  5. 9 - log 7,1

N. Puji

Master Teacher

Mahasiswa/Alumni Universitas Sebelas Maret

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style Mol space CH subscript 3 COOH space equals space straight M space cross times space straight V space equals space 0 comma 1 space straight M space cross times space 50 space mL space equals space 50 space mmol  Mol space NaOH space equals space straight M space cross times space straight V space equals space 0 comma 1 space straight M space cross times space 50 space mL space equals space 5 space mmol  Persamaan space reaksi colon  space space space space space space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold CH subscript bold 3 bold COOH bold left parenthesis bold aq bold right parenthesis bold space bold plus bold space bold NaOH bold left parenthesis bold aq bold right parenthesis bold space bold rightwards arrow bold space bold CH subscript bold 3 bold COONa bold left parenthesis bold aq bold right parenthesis bold space bold plus bold space bold H subscript bold 2 bold O bold left parenthesis bold l bold right parenthesis  Mula minus mula space colon space space space space space space space space 5 space mmol space space space space space space space space space space space space 5 space mmol space space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space minus  Reaksi space space space space space space space space space colon space space space space minus 5 space mmol space space space space space space space space space minus 5 space mmol space space space space space space space space space space space space space space plus space 5 space mmol space space space space space space space plus space 5 mmol  stack Sisa space space space space space space space space space space space space space colon space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space space 5 space mmol space space space space space space space space space space space space 5 space mmol with bar on top  Karena space yang space tersisa space hanya space garam space dan space air comma space maka space menggunakan space rumus space hidrolisis. space  left square bracket straight G right square bracket space equals fraction numerator m m o l over denominator m L space v o l u m e end fraction space equals space fraction numerator 5 space m m o l over denominator 100 space m L end fraction equals space 5.10 to the power of negative 2 end exponent space straight M  OH space equals square root of fraction numerator K w over denominator K a end fraction left square bracket G right square bracket end root space equals square root of 10 to the power of negative 14 end exponent over 10 to the power of negative 5 end exponent x space 5 space. space 10 to the power of negative 2 end exponent end root space equals 7 comma 1 space straight x space 10 to the power of negative 6 end exponent  pOH equals space minus space log space left square bracket OH minus right square bracket  space space space space space space space equals space minus log space cross times space 7 comma 1 space 10 to the power of negative 6 end exponent space equals space 6 space minus space log space 7 comma 1  pH equals space 14 minus space left parenthesis 6 minus space log space 7 comma 1 right parenthesis equals 8 space plus space log space 7 comma 1 end style

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Sebanyak 100 mL KOH 0,04 M dicampur dengan 100 mL HCOOH 0,04 M menurut reaksi: KOH (aq) + HCOOH (aq) → HCOOK (aq) + H2O (l) Jika Ka HCOOH = 2.10-4 dan Kw = 10-14, pH campuran tersebut sebesar ....

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