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Jika 200 mL NH4​OH 0,8 M direaksikan dengan 200 mL larutan HCl 0,8 M (Kb NH3​=10−5). Tentukan pH larutan setelah bereaksi!

Pertanyaan

Jika 200 mL begin mathsize 14px style N H subscript 4 O H end style 0,8 M direaksikan dengan 200 mL larutan undefined 0,8 M undefined. Tentukan pH larutan setelah bereaksi!

I. Solichah

Master Teacher

Jawaban terverifikasi

Jawaban

pH larutan setelah bereaksi adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank 5 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus sign end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank log end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 2 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank. end table

Pembahasan

Di dalam air, garam akan terionisasi dan apabila ion garam bereaksi dengan air maka akan terjadi reaksi hidrolisis. Garam yang anionnya berasal dari asam kuat dan kationnya berasal dari basa lemah jika dilarutkan dalam air akan mengalami hidolisis parsial yang bersifat asam.

Tahapan yang dapat dilakukan

  • Menghitung mol N H subscript 4 O H

table attributes columnalign right center left columnspacing 0px end attributes row cell mol space N H subscript 4 O H end cell equals cell M cross times V end cell row blank equals cell 0 comma 8 space M cross times 200 space mL end cell row blank equals cell 160 space mmol end cell end table
 

  • Menghitung mol H Cl

table attributes columnalign right center left columnspacing 0px end attributes row cell mol space H Cl end cell equals cell M cross times V end cell row blank equals cell 0 comma 8 space M cross times 200 space mL end cell row blank equals cell 160 space mmol end cell end table
 

  • Masukkan ke tabel MRS
     


 

  • Yang tersisa adalah garam yang berasal dari asam kuat dan basa lemah = hidrolisis parsial asam.
  • Menghitung molaritas garam yang terbentuk

table attributes columnalign right center left columnspacing 0px end attributes row cell M space N H subscript 4 Cl end cell equals cell fraction numerator mol space N H subscript 4 Cl over denominator volume space total end fraction end cell row blank equals cell fraction numerator 160 space mmol over denominator 200 space mL plus 200 space mL end fraction end cell row blank equals cell fraction numerator 160 space mmol over denominator 400 space mL end fraction end cell row blank equals cell 0 comma 4 space M end cell row blank equals cell 4 cross times 10 to the power of negative sign 1 end exponent space M end cell end table
 

  • Menghitung open square brackets H to the power of plus sign close square brackets larutan

space N H subscript 4 Cl space space space space space space space space rightwards arrow space space space space space N H subscript 4 to the power of plus space space space plus space space space space Cl to the power of minus sign 4 cross times 10 to the power of negative sign 1 end exponent space M space space space space space space 4 cross times 10 to the power of negative sign 1 end exponent space M space space space space space 4 cross times 10 to the power of negative sign 1 end exponent space M  

 

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of Kw over Kb cross times left square bracket Kation space N H subscript 4 Cl right square bracket end root end cell row blank equals cell square root of 10 to the power of negative sign 14 end exponent over 10 to the power of negative sign 5 end exponent cross times 4 cross times 10 to the power of negative sign 1 end exponent end root end cell row blank equals cell square root of 4 cross times 10 to the power of negative sign 10 end exponent end root end cell row blank equals cell 2 cross times 10 to the power of negative sign 5 end exponent end cell row blank blank blank end table 

  • Menghitung pH larutan

table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row blank equals cell negative sign log space 2 cross times 10 to the power of negative sign 5 end exponent end cell row blank equals cell 5 minus sign log space 2 end cell end table 
 

Jadi, pH larutan setelah bereaksi adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank 5 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus sign end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank log end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 2 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank. end table

2rb+

5.0 (4 rating)

Pertanyaan serupa

Diketahui larutan 0,1 M NH4​Cl dan Kb​ NH4​OH=10−5 Tuliskan hidrolisis garam NH4​Cl! Hitung harga Kh​, [H+], [OH−] dan pH larutan!

373

4.2

Jawaban terverifikasi

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