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Pertanyaan

J1ka x = 25 dan y = 64, maka nilai y 3 1 ​ − x 2 1 ​ x − 2 3 ​ . 3 y 2 ​ ​ = ...

J1ka x = 25 dan y = 64, maka nilai

  1. -2.000

  2. negative 16 over 125

  3. 16 over 125

  4. 2.000

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N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

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Pembahasan

fraction numerator x to the power of negative begin display style 3 over 2 end style end exponent. cube root of y squared end root over denominator y to the power of begin display style 1 third end style end exponent minus x to the power of begin display style 1 half end style end exponent end fraction  equals fraction numerator 25 to the power of negative begin display style 3 over 2 end style end exponent. cube root of 64 squared end root over denominator 64 to the power of begin display style 1 third end style end exponent minus 25 to the power of begin display style 1 half end style end exponent end fraction equals fraction numerator open parentheses 5 squared close parentheses to the power of negative begin display style 3 over 2 end style end exponent. left parenthesis left parenthesis 2 to the power of 6 right parenthesis squared right parenthesis to the power of begin display style 1 third end style end exponent over denominator open parentheses 2 to the power of 6 close parentheses to the power of begin display style 1 third end style end exponent minus left parenthesis 5 squared right parenthesis to the power of begin display style 1 half end style end exponent end fraction  equals fraction numerator 5 to the power of negative 3 end exponent.2 to the power of 4 over denominator 2 squared minus 5 end fraction equals fraction numerator 5 to the power of begin display style 1 third end style.16 end exponent over denominator 4 minus 5 end fraction equals negative 16 over 125

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